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Elanso [62]
2 years ago
14

Which of the following are examples of physical properties of ethanol? Select all that apply.

Chemistry
1 answer:
bazaltina [42]2 years ago
7 0
Ethanol is: flammable, liquid at room temperature, the boiling point is 78.37 ° C.
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You have dissolved 10 g sodium oxide in 200 ml water.calculate concentration of the solution
e-lub [12.9K]

Answer:

0.85 Molar Na2O

Explanation:

Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).

 (10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.

Molar is a measure of concentration.  It is defined as moles/liter.  A 1 M  solution contains 1 mole of solute per liter of solvent.  [200 ml water = 0.2 Liters water.]

In this case, we have 0.161 moles Na2O in 0.200 L of solvent.

 (0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O

8 0
1 year ago
When wood burns, the mass of the ash is less than the mass of the original wood. Yet the law of conservation of matter says that
satela [25.4K]

Explanation:

According to the law of the conservation of mass, 'mass is conserved in a chemical reaction. The mass cannot be created nor be destroyed in a chemical process'.

This law holds true for the burning of wood also. Although the wood burns to produce ash which weighs less than wood but also, it produces some soot and other gases and the sum of the masses of all these is equal to the sum of the masses of wood and oxygen that reacted with it.

7 0
2 years ago
A square painting has a length of 62 cm.<br><br> What is the area of the painting?<br><br> cm²
svetlana [45]

Answer:3844 cm^2

Explanation:

62 squared since it is a square, and area is base times height

3 0
3 years ago
What do noble gases all have in common?
erastova [34]

Answer:

D. They react readily with oxygen in the air

3 0
2 years ago
Ultraviolet radiation has a frequency of 6.8×1015 Hz. What is the energy associated with this frequency?
stellarik [79]

Use Planck's equation (E=hv) to solve.  where <span>frequency (v) of ultrviolet radiation is 6.8 × 1015 1/s.  </span><span> </span>The variable h is a constant equal to 6.63 × 10-34 J·s
E= <span>(6.8 × 1015 1/s)x(</span>6.63 × 10-34 J·s)


5 0
3 years ago
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