Answer:
6.23 KOH 90% son necesarios
Explanation:
Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.
Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:
<em>Equivalentes KOH:</em>
0.100L * (1eq / L) = 0.100eq = 0.100moles
<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>
0.100moles * (56.1056g/mol) = 5.61 KOH se requieren
<em>KOH 90%:</em>
5.61g KOH * (100g KOH 90% / 90g KOH) =
<h3>6.23 KOH 90% son necesarios</h3>
The chemical equation for this combustion reaction is:
<span>C8H18 + O2
--> CO2 + H2O</span>
Balancing by adding whole number coefficients:
<span>2 C8H18 + 25
O2 --> 16 CO2
+ 18 H2O</span>
Including the phases:
<span>2 C8H18 (l) + 25 O2
(g) --> 16 CO2 (g) + 18 H2O (l)</span>
<span>where g is gas and l is liquid</span>
Answer:
ionize
Explanation:
Acids are chemical substances that lose/donate their hydrogen ion (H+) when they react with water. This property of acids is termed IONIZATION. In a chemical reaction involving acids and bases, acids release their proton or hydrogen ion (H+) in the presence of water solutions to form a conjugate base, which is usually an anion.
For example, in the chemical reaction;
HX + H20 -------> X- + H30+
HX is the acid because it loses its electron to water and forms the anion, X-, which is the conjugate base. Hence, it can be said that acid HX ionizes in water.
The molecular geometry is trigonal planar. I would choose E
