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3 years ago

What is the mass, in grams, of solute in 255mL of a 0.0525M solution of KMnO4 (MM =

Chemistry

1 answer:

Murljashka [212]3 years ago

4 0

Answer:

Mass = 2.12 g

Explanation:

Given data:

Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)

Molarity = 0.0525 M

Mass in gram = ?

Solution:

First of all we will calculate the number of moles.

<em>Molarity = number of moles of solute / volume in litter</em>

0.0525 M = number of moles of solute / 0.255 L

Number of moles of solute = 0.0525 M ×0.255 L

Number of moles of solute = 0.0134 mol

Mass in gram:

<em>Number of moles = mass/ molar mass</em>

Mass = moles × molar mass

Mass = 0.0134 mol × 158.04 g/mol

Mass = 2.12 g

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