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Stels [109]
3 years ago
9

What is state symbols

Chemistry
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

Explanation:

State symbols are used in chemical equations to delineate the state of matter in which the reaction is taking place.

They give a good perspective of the state of the reactants and products obtainable.

There are basically four states of matter in every chemical reaction:

  • Solids are symbolized by small letter (s)
  • Liquids are represented by (l)
  • Gases are shown by (g)
  • Aqueous solutions having water as the medium by (aq)

These symbols appear as subscript in front of the chemical species.

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Ethylene glycol (C2H6O2) is used as an antifreeze in cars. If 250 g of ethylene glycol is added to 3.00 kg of water, what is the
Zepler [3.9K]

Answer:

2,909 M

Explanation:

molair mass is of.ethylene is 26,04 g/mol

first you need to calculate how much mL 3 kg is. You can do this by using the density of ethylene: 1,1 g/mL.

3000 g x 1.1 = 3300 mL = 3,3 L

Next you need to calculate the amount of moles:

250 g / 26,04 g/mol = 9,60 mol

Now you can calculate the molarity:

9,6/3.3 = 2,909 M

I don't know the answer for the second question. I'm sorry.

3 0
3 years ago
why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis
Helga [31]

<u>Answer:</u>

<u>Plasmas of great interest to scientists or manufacturers as</u>

  • Plasma is electrically charged gases that contain considerable charged particles that can change the behavior of the substance.

<u>Current uses of plasmas:</u>

  • First, it is used to make semiconductors for different types of electronic equipment
  • Secondly, they're used in making transmitters for high-temperature films.

<u>Way scientists and engineers hope to use plasmas in the future:</u>

  • The scientists are hoping to use plasma in the future to get rid of all hazardous wastes through a process called plasma gasification.

6 0
3 years ago
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
Can somebody plz just answer this 1 question thx!!!
coldgirl [10]

Answer:

cetacean i think thats the answer

3 0
3 years ago
Complete combustion of 6.4g of compound K produced 8.8 g of carbon dioxide and 7.2 g of water. Calculate the empirical formula o
Elenna [48]
Lh (x1)78.009+1= 0.0000567
7 0
3 years ago
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