All categories

3 years ago

Question 20 (Essay Worth 8 points)

Chemistry

2 answers:

sleet_krkn [62]3 years ago

8 0

Answer: The correct answer is c

Explanation: its is the right answer

KIM [24]3 years ago

4 0

Answer:

See explanation

Explanation:

FeCl3 +3 NaOH →3 NaCl + Fe(OH)3

One mole of ferric chloride reacts with three moles of sodium hydroxide to yield three moles of sodium chloride and one mole of ferric hydroxide. The reaction demonstrate the law of conservation of mass because the total mass of reactants equals the total masses of products formed.

b) neutralization reaction

c) lead is lower than zinc in the activity series of metals but calcium is higher than zinc hence zinc cannot displace calcium but it can displace lead.

d) the half life is 21 hours

e) it will take 320g grams 21 hours to remain 160g

It will take 160g 42 hours to remain 80g

It will take 80g 63 hours to remain 40g

It will take 40g 84 hours to remain 20g

It will take 20g 105 hours to remain 10g

It will take 10g 126 hours to remain 5g

It will take 5g 147 hours to remain 2.5g

You might be interested in

Calculate the solubility of Mg(OH)2 in water at 25 C. You'll find Ksp data in the ALEKS Data tab. Round your answer to significa

elena-s [515]

Answer:

1.12 × 10⁻⁴ M

Explanation:

Step 1: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

I 0 0

C +S +2S

E S 2S

The solubility product constant is:

Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³

S = 1.12 × 10⁻⁴ M

8 0

3 years ago

How many liters of a 2.0 M solution of HCl do you need to have 8.0 moles of HCI?

kakasveta [241]

Answer:

1M HCl: add 1mol/12M = 83 ml conc. HCl to 1L of water or 8.3ml to 100ml.

2M HCl: add 2mol/12M = 167 ml conc. HCl to 1L of water or 16.7ml to 100ml.

4 0

3 years ago

8 moles Cl to grams 3

kirill [66]

Answer: I don’t understand what your asking elaborate more

Explanation:

7 0

3 years ago

A solution of the primary standard potassium hydrogen phthalate (KHP), KHC8H4O4 , was prepared by dissolving 0.4877 g of KHP in

Flura [38]

<u>Answer:</u> The concentration of KOH solution is 0.103 M.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of KHP = 0.4877 g

Molar mass of KHP = 204.22 g/mol

Putting values in equation 1, we get:

$\text{Moles of KHP}=\frac{0.4877g}{204.22g/mol}=0.0024mol$

The chemical reaction for the reaction of KHP with KOH follows:

$KHC_8H_4O_4(aq.)+KOH\rightarrow K_2C_8H_4O_4(aq.)+H_2O(l)$

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of KOH.

So, 0.0024 moles of KHP will react with = $\frac{1}{1}\times 0.0024=0.0024mol$ of KOH.

To calculate the molarity of KOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Moles of KOH = 0.0024 moles

Volume of solution = 23.22 mL = 0.02322L (Conversion factor: 1L = 1000 mL)

Putting values in above equation, we get:

$\text{Molarity of KOH }=\frac{0.0024mol}{0.02322L}=0.103M$

Hence, the molarity of KOH solution is 0.103 M.

6 0

3 years ago

The correct name for Cu(CN), is: *

garik1379 [7]

Answer:

Copper dicyanide CUPRIC CYANIDE Copper cyanide (Cu(CN)2) Cyanure de cuivre copper (II) cyanide More...

Explanation:

HOPE THIS HELPS :)

8 0

3 years ago