To solve this problem, let us all convert the mass of
each element into number of moles using the formula:
moles = mass / molar mass
Where,
molar mass K = 39.10 g / mol
<span>molar mass Cl = 35.45 g / mol</span>
molar mass O = 16 g / mol
<span>and mass O = 13 g – 4.15 g
– 3.76 g = 5.09 g</span>
moles K = 4.15
g / (39.10 g / mol) = 0.106 mol
<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>
moles O = 5.09 g / (16 g /
mol) = 0.318 mol
The ratio becomes:
0.106 K: 0.106 Cl: 0.318 O
We divide all numbers with
the smallest number, in this case 0.106. This becomes:
K: Cl: 3O
Therefore the empirical formula
is:

The mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
<h3>Calculating mass of a compound </h3>
From the question, we are to determine the mass of the given beryllium sulfide.
From the given information,
Number of moles of beryllium sulfide (BeS) given = 2.42 moles
Using the formula,
Mass = Number of moles × Molar mass
Molar mass of BeS = 41 g/mol
Then,
Mass of BeS = 2.42 × 41
Mass of BeS = 99.22
Mass of BeS ≅ 99.2 g
Hence, the mass in grams of the given beryllium sulfide is 99.2 g. The correct option is the second option - 99.2 g BeS
Learn more on Calculating mass of a compound here: brainly.com/question/18142599
Spotted Lantern: Destroying our trees
Fishers: Brought to lower numbers of certain species, but have dramatically lowered other species.
Zebra Mussels: Clog pipes
Emerald Ash Borer: Ruins ash trees that provide us with durable wood.
Answer:
Sulfur dioxide is a covalent bond because we have two non-metals (Sulfur and Oxygen).
(<em>Sulfur dioxide formula)</em>
It's called Sulfur dioxide but it can be called Sulfurous anhydride and Sulfur (lV) oxide.
Sulfur dioxide can have different reactions:
-
In the presence of oxygen oxidation of sulfur dioxide to sulfur trioxide occurs and the formula is:

The equal is because it's a reversible equation. This reaction is spontaneous.
- The sulfur trioxide reacting with water produces sulfuric acid. The formula is:

- Also the sulfur dioxide reacting with sodium hydroxide produces sodium sulfite and the formula is:

- And finally we have the reduction of sulfur dioxide (it can be in presence of hydrogen sulfide) getting elemental sulfur and water. The formula is:
