Answer:
1. four in the first energy level, four in the second energy level
2. eight in the first energy level, zero in the second energy level
3. zero in the first energy level, eight in the second energy level
4. two in the first energy level, six in the second energy level *
Explanation:
1. four in the first energy level, four in the second energy level
2. eight in the first energy level, zero in the second energy level
3. zero in the first energy level, eight in the second energy level
4. two in the first energy level, six in the second energy level *
The answer to the question asked above is that in a Molecular Solid, the substance just dissolves into the solution when added to water but ionic solid does not.
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When cool, dense air from over the water flows inland, it's called a sea breeze.
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When 0.34 of HNO₃ is titrated to equivalence using 0.14 l of 0.1 m NaOH then the concentration of HNO₃ is 0.041 M
The reaction of neutralization of HNO₃ with NaOH is
HNO₃ + NaOH → H₂O + NaNo₃
When 1 mole of HNO₃ react with 1 mole of NaOH, based on chemical rection the moles of NaOH at equivalence point are equal to moles of HNO₃ present in solution: -
With the mole and volumes, we can find molarity as follows:
Moles of NaOH = moles HNO₃
⁼ 0.14 L X (0.1 mol NaOH/L) = 0.014 mole NaOH
=0.014 mol HNO₃
Molarity: -

= 0.041 M
Thus, from above solution we concluded that the concentration of HNO₃ solution is 0.041 M.
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The substance that is in the smaller amount is the solute. so yes, the answer is true.