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3 years ago

What is subshell and why do we use it if we have main shells already

1 answer:

5 0

Principal shell shows the main energy level, in that there are some more energy levels. This is how the atomic structure is defined according to the Quantum Mechanical model of atom. So exactly why do subshells exist and all i don't know

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The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?

Sauron [17]

1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
= 4/3 (3.142 ×12.167×10∧-24
= 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³

8 0

3 years ago

For an organism’s scientific names, the first part is the ________ and the second is the ________.

kari74 [83]

Answer:

Explanation:

For an organism scientific names the first part is the genus and the second is the species

3 0

2 years ago

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An iron ore contains 39% Fe2O3 by mass. What is the maximum mass of iron that can be recovered from 13.2 kg of this ore?

Mars2501 [29]

Answer:

3.6036

Explanation:

0.39 * 13.2 = 5.148

5.148 * 0.7 = 3.6036

Fe2O3 = 0.7

6 0

3 years ago

Determine the molar mass of CuSO4 (the solute) in a 1.0M aqueous solution of CuSO4

inna [77]

Answer:

See explanation.

Explanation:

Hello,

In this case, we could have two possible solutions:

A) If you are asking for the molar mass, you should use the atomic mass of each element forming the compound, that is copper, sulfur and four times oxygen, so you can compute it as shown below:

$M_{CuSO_4}=m_{Cu}+m_{S}+4*m_{O}=63.546 g/mol+32.00g/mol+4*16.00g/mol\\\\M_{CuSO_4}=159.546g/mol$

That is the mass of copper (II) sulfate contained in 1 mol of substance.

B) On the other hand, if you need to compute the moles, forming a 1.0-M solution of copper (II) sulfate, you need the volume of the solution in litres as an additional data considering the formula of molarity:

$M=\frac{n_{solute}}{V_{solution}}$

So you can solve for the moles of the solute:

$n_{solute}=M*V_{solution}$

Nonetheless, we do not know the volume of the solution, so the moles of copper (II) sulfate could not be determined. Anyway, for an assumed volume of 1.5 L of solution, we could obtain:

$n_{solute}=1mol/L*1.5L=1.5mol$

But this is just a supposition.

Regards.

4 0

3 years ago

What element is in group 17 and period 3 of the periodic table?

Anastasy [175]

Answer:

Chlorine is the element located in period 3, group 17 of the periodic table.

Explanation:

6 0

3 years ago

Read 2 more answers