Either protons or neutrons
        
                    
             
        
        
        
how would it be possible to even be absorbed?? the answer is released. 
 
        
             
        
        
        
Answer: The molarity of each of the given solutions is:
(a) 1.38 M
(b) 0.94 M
(c) 1.182 M 
Explanation:
Molarity is the number of moles of a substance present in liter of a solution.
And, moles is the mass of a substance divided by its molar mass.
(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

Now, molarity of ethanol solution is as follows.

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

Now, molarity of sucrose solution is as follows.

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

Now, molarity of sodium chloride solution is as follows.

Thus, we can conclude that the molarity of each of the given solutions is:
(a) 1.38 M
(b) 0.94 M
(c) 1.182 M 
 
        
             
        
        
        
<span>The mass and volume of each sample differ from the mass and volume of the other samples. Is it possible for each sample to contain 1 mol of each substance?
</span><span>C) Yes, because the number of moles is not dependent on the mass or the volume.</span>
        
                    
             
        
        
        
Answer:
the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M
Explanation:
Given that :
a student dissolves 6.64 g of CoF₂  into 500 mL of water 
volume of the solution(water) = 500 mL = 0.50 L
The standard  molar mass of CoF₂ is 96.93 g/mol
number of moles of CoF₂ = mass of CoF₂/molar mass of CoF₂
number of moles of CoF₂ = 6.64 g/96.93 g/mol
number of moles of CoF₂ = 0.0685 mol
The molarity of any given substance is known to be as the number of moles of solute dissolved in one litre of solution.
Thus ;
Molarity of  cobalt(II) fluoride CoF₂ in the resulting solution is = number of moles / Volume in (L)
Molarity of  cobalt(II) fluoride CoF₂  = 0.0685 mol/ 0.50 L
= 0.137  M
Thus ; the molarity of cobalt(II) fluoride in the resulting solution is = 0.137  M