Question

An 8.0 kilogram cart moving to the right at 4.0 meters per second about to make a head-on collision with a 4.0 kilogram cart moving to the left at 6.0 per second. After the collision, the 4.0 kilogram cart moves to the right at 3.0 meters per second. What is the velocity of the 8.0 kilogram cart after the collision?

Answer 1

Well 4:6=?:3. Your answer is 2.
6/2=3
4/2=2

Hoped I helped!

Answer 2

Answer:

v = -0.5 m/s

Explanation:

According to law of conservation of energy, in the absence of any external force, the momentum of a system remains conserved.

Initial momentum = final momentum

m u + m' u' = m v + m' v'

where, m = 8.0 kg

m' = 4.0 kg

u = 4.0 m/s

u' = -6.0 m/s

v' = 3.0 m/s

v = ?

⇒ (8.0)(4.0)+(4.0)(-6.0)=(8.0)(v)+(4.0)(3.0)

⇒ 32-24=8v+12

⇒v = -0.5 m/s

The 8.0 kg cart will move with 0.5 m/s towards left.