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4 years ago

Need help with exercises 3,4,5 Will give brainliest!!!

Physics

1 answer:

Harman [31]4 years ago

4 0

I pretty sure that 3 is b and 4 is A and 5 I need a full picture

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What weight of water is displaced by a 100-ton floating ship? What is the buoyant force that acts on this ship?

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3 years ago

The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. The heat increased the _

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3 years ago

Read 2 more answers

A 1.25 x 10-4 C charge is moving5200 m/s at 37.0° to a magnetic fieldof 8.49 x 10-4 T. What is the magneticforce on the charge?

juin [17]

0.0003321 Newtons

Explanation

We are given the charge, its velocity, and the magnetic field strength and direction. We can thus use the equation to find the force

$\begin{gathered} F=qvBsinθ \\ where\text{ F is the magnetic force} \\ q\text{ is the charge} \\ v\text{ is the velocity of the charge} \\ Bis\text{ the magnetic field} \\ \theta\text{ is the angle} \end{gathered}$

Step 1

Let

$\begin{gathered} q=1.25*10^{-4\text{ }}C \\ v=5200\frac{m}{s} \\ \theta=37\text{ \degree} \\ B=8.49*10^{-4}T \end{gathered}$

now, replace

$\begin{gathered} F=qvBs\imaginaryI n\theta \\ F=1.25*10^{-4}\text{ C*5200 }\frac{m}{s}*8.49*10^{-4}Tsin(37) \\ F=0.0003321\text{ Newtons} \\ \end{gathered}$

so, the answer is

0.0003321 Newtons

I hope this helps you

7 0

1 year ago

Anyone know what type of circuit this is?

Oksana_A [137]

Answer:

Explanation:

BECAUSE ITS GOING ON AND ON IF ITS NOT CORRECT I WILL VOTE YOU BRAINLEST ON MY QUESTION

3 0

3 years ago

Vectors A and B lie in the xy ‑plane. Vector A has a magnitude of 17.1 and is at an angle of 150.5∘ counterclockwise from the +x

IRINA_888 [86]

Answer:

A = -14.87 i ^ + 8.42 j ^ + 0 k ^

B = -25.41 i ^ -12.0 j ^ + 0 k ^

Explanation:

For this exercise let's use trigonometry by decomposing to vectors

vector A

module 17.1 with an angle of 150.5 counterclockwise.

Sin 150.5 = $A_{y}$ / A

cos 150.5 = Ax / A

A_{y} = A sin 150.5 = 17.1 sin 150.5

Aₓ = A cos 1505 = 172 cos 150.5

A_{y} = 8,420

Aₓ = -14.870

the vector is

A = -14.87 i ^ + 8.42 j ^ + 0 k ^

Vector B

$B_{y}$ = 28.1 sin 205.3

Bₓ = 28.1 cos 205.3

B_{y} = -12.009

Bₓ = -25.405

the vector is

B = -25.41 i ^ -12.0 j ^ + 0 k ^

5 0

3 years ago