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4 years ago

HELP FAST 20 POINTS

Chemistry

2 answers:

schepotkina [342]4 years ago

8 0

D) Transportation is the correct answer

Naddik [55]4 years ago

7 0

The answer is D because it’s the movement of food substance from the stems to growing tissues and storage tissues,
The answer A is incorrect because it talks about the cycle

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If 50% of a radioactive element remains after 4000 years, what is the half-life?

ANTONII [103]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

If 50%, or half, of the element remains after 4000 years, that means the half life must be 4000 years.

Hope this helps!

4 0

4 years ago

The equilibrium constant, Kc, for the following reaction is 3.61×10-4 at 426 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar

iogann1982 [59]

Answer:

the concentration of PCl5 in the equilibrium mixture = 296.20M

Explanation:

The concept of equilibrium constant was applied where the equilibrium constant is the ration of the concentration of the product over the concentration of the reactants raised to the power of their coefficients. it can be in terms of concentration in M or in terms of Pressure in atm.

The detaied steps is as shown in the attached file.

8 0

3 years ago

What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm? Law used:

ladessa [460]

Using Charles's law; which states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure.
That is; V α T
Hence; V1/T1 = V2/T2 = constant
V2 = V1 × (T2/T1)
= 250 × (350/300) = 291.67 mL
Therefore; the new volume will be 291.67 mL

3 0

3 years ago

Read 2 more answers

Calculate the solubility (in mol/L) of Fe(OH)3 (Ksp = 4.0 x 10^-38) in each of the following situations:

netineya [11]

Answer:

(A) 1.962x10^-10 M solubility in pure water

(B) 4.0 x 10^-33 M solubility

(C) 4.0 x 10^-27 M solubility

Explanation:

(A) Fe(OH)3 would give (Fe3+) and (3OH-)

Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

Let y = [Fe^3+]

Let 3y = [OH-]

4x10^-38 = (y)(3y)^3

4x10^-38 = 27y^4

y^4 = 4x10^-38 ÷ 27

y^4 = 1.481 x 10^-39

y = 1.962x10^-10 M solubility in pure water

(B) pH = 5.0

5.0 = - log [OH-]

-5.0 = log [OH-]

[OH-] = 10^-5.0 = 1.0 x 10^-5 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-5] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-5

= 4.0 x 10^-33 M solubility

11.0 = - log [OH-]

-11.0 = log [OH-]

[OH-] = 10^-11.0 = 1.0 x 10^-11 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-11] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-11

= 4.0 x 10^-27 M solubility

6 0

3 years ago

According to P1V1 = PzV2

Zolol [24]

Answer:

a., c.

Explanation:

P1V1 =P2V2 is true when T is constant and number of moles n is constant also.

3 0

4 years ago