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spayn [35]
3 years ago
11

How many significant figures are in 195.01

Chemistry
1 answer:
Masja [62]3 years ago
5 0

Answer:

difficult to answer, need a bit more detail

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PLEASE ANSWER
lisov135 [29]

Answer:

B.

Explanation:

8 0
3 years ago
Name two compounds with more exothermic lattice energies than scandium oxide and justify your choice.
N76 [4]

Answer:

1 . Al_2O_3

2. TiO_2

Explanation:

The more stable the ionic compound, the more is it lattice energy.

  • The more the charge on the cation and the anion, the greater is the lattice energy.
  • The less the size of the cation and the anion, the greater is the lattice energy.

Scandium oxide (Sc_2O_3) is an oxide in which Sc^{3+} behaves as cation and O^{2-} behaves as anion.

The compounds which has higher lattice energy than scandium oxide are:

1 . Al_2O_3

This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation Al^{3+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

2. TiO_2

This is because the charge on the cation Ti^{4+} is greater than that of Sc^{3+} and also the size of the cation Ti^{4+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

3 0
3 years ago
What is the central atom of C2H4Br2
Korvikt [17]

Answer:

1.2,dibromoethane is the sha'awa .

6 0
3 years ago
What conversion factor does a balanced chemical equation give you?
Dmitriy789 [7]
From google but i can explain further if needed. <span> The </span>balanced<span> equation for the reaction of interest contains the stoichiometric ratios of the reactants and products; these ratios </span>can<span> be used as </span>conversion factors<span> for mole-to-mole </span>conversions<span>.</span>
7 0
3 years ago
Part A
den301095 [7]

Answer:

n_{Cl_2}=0.3molCl_2

Explanation:

Hello there!

In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:

n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}

So we cancel out the moles of NaCl to obtain:

n_{Cl_2}=0.3molCl_2

Best regards!

3 0
3 years ago
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