How many grams are in 1.946 moles of NaCl

Realice una historieta que resuma su comprensión acerca de la teoría atómica y los diferentes modelos atomicos que se

Tomtit [17]

Respuesta:

Los modelo atómicos han permitido representar el modo de funcionamiento de los átomos. A lo largo de la historia han surgido un numero de modelos atómicos diferentes incluyendo los modelos de Bohr, Thomson, Rutherford, Sommerfeld, Dalton y Schrödinger.

Explicación:

El modelo atómico propuesto por John Dalton (1808) demostró que las sustancias químicas reaccionan en proporciones fijas y cómo mediante su combinación se producen elementos diferentes. Dalton fue el primero en postular la existencia de elementos indivisibles llamados átomos. A continuación, Thomson (1904) desarrolló un modelo en el cual el átomo estaba compuesto por protones con carga positiva y electrones con carga negativa los cuales se incrustaban uniformemente dentro de este átomo, asemejándose a las pasas de uva de un budín. En 1911, Ernest Rutherford desarrolló un nuevo modelo donde la masa principal del átomo tenía carga positiva y se localizaban en el núcleo, mientras que los electrones con carga negativa se posicionaban en la región externa del átomo. Subsecuentemente, Niels Bohr (1913) represento el funcionamiento del átomo de hidrógeno mediante un protón inmóvil en el núcleo atómico y un electrón girando a su alrededor. El modelo atómico de Sommerfeld permitió generalizar el diagrama de Bohr a otros tipos de átomos mas allá del Hidrógeno, incluyendo diferentes niveles energéticos para cada átomo particular. El modelo de Schrödinger (1926) permitió corregir aquellas discordancias surgidas del modelo atómico de Bohr. Schrödinger incluyó diferentes niveles y subniveles de energía a los electrones e incorporó órbitas elípticas a su movimiento, con lo cual permitiendo predecir los efectos relativos de los campos magnético y eléctrico sobre el movimiento de los electrones.

4 0

3 years ago

C. Use Hess's law and the following equations to calculate ΔH for the reaction 4NH3 (g) + 5O2 (g) 4NO(g) + 6H2 O(g). Show your w

Monica [59]

Considering the Hess's Law, the enthalpy change for the reaction is -906.4 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 N₂ + 6 H₂ → 4 NH₃ ΔH = –183.6 kJ/mol

Equation 2: 2 N₂ + 2 O₂ → 4 NO ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂ ΔH = 183.6 kJ/mol

Equation 2: 2 N₂ + 2 O₂ → 4 NO ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

Finally, the enthalpy change for the reaction is -906.4 kJ/mol.

Learn more about Hess's law:

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7 0

2 years ago

Give the chemical symbol of an element in the third period (row) of the periodic table with four 3p electrons.

Ann [662]

<u>Answer: </u>The chemical symbol of the element is Sulfur.

<u>Explanation:</u>

The element which is present in third period of the periodic table having four 3p electrons is Sulfur. Sulfur is the 16th element of the periodic table which has 6 valance electrons.

The electronic configuration of this element is: $[Ne]3s^23p^4$

This element is considered as a non-metal because it will accept electrons in order to attain stable electronic configuration.

Hence, the chemical symbol of the element is Sulfur.

7 0

3 years ago

HELP IM TIMEDDDDDDDDDDDD

nadya68 [22]

Answer:

ethier a dessert or a plains

though plains can get rain in the summer

from me living in both

it seems more like a dessert

3 0

3 years ago

Read 2 more answers

1.5L of water is boiled to steam at a temperature of 100°C and creates 3.5atm of pressure on the container. How many moles of st

Anna71 [15]

Answer: 1.7 moles

Explanation:

Given that:

Volume of water V = 1.5L

(since 1 liter = 1dm3

1.5L = 1.5dm3)

Temperature T = 100°C

Convert Celsius to Kelvin

(100°C + 273 = 373K)

Pressure P = 3.5 atm

Number of moles of steam N = ?

Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

3.5atm x 1.5dm3 = n x (0.0082 ATM dm3 K-1 mol-1 x 373K)

5.25 = n x 3.06

n = 5.25/3.06

n = 1.7 moles

Thus, 1.7 moles of steam is present

3 0

3 years ago