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andriy [413]
3 years ago
5

What is one way you can state how you feel?

Physics
2 answers:
faust18 [17]3 years ago
7 0
Emotions, Body action and much more
inysia [295]3 years ago
3 0
Through emotion, facial expressions, body language, etc...

hope this helps
You might be interested in
A freight car with a mass of 10 metric tons is rolling at 108 km/h along a level track when it collides with another freight car
Rufina [12.5K]

Answer:

20 metric tons

Explanation:

Using the Principle of Conservation of Linear Momentum which states that the total momentum of a system is constant in any direction in which no external force acts.

momentum before collision= momentum after collision

mathematically expressed as

m1u1 + m2u2 = m1v1+m2v2 =0

where:

m1= mass of rolling freight car = 10 metric tons = 10Mg

1 ton = 1000kg= 1Mg

u1 =initial velocity of freight car = 108km/h,

m2 = mass of stationary freight car = ?, this the unknown we are finding

u2 = initial velocity of

m2 = 0, because it is at rest,

v1= final velocity of m1,

v2= final velocity of m2

since they move together in the same direction they share a common final velocity as such

v1=v2= 36km/h

substituting valves in expression give

m1u1 + m2u2 = m1v1 + m2v2= 0

10Mgx 108km/hr + m2 x 0 = 10Mg x 36km/h + m2x36km/h

1080( Mg x km/hr) + 0 = 360 (Mg x Km/h) + 36m2 (km/h)

1080 (Mgx km/hr) - 360(Mg x km/h) = 36m2 (km/h)

720(Mg x km/h) = 36m2 (km/h)

divide both side by  36 (km/h) gives

m2 = 20Mg =20 metric tons

3 0
3 years ago
Day and night are caused by the earths blank
professor190 [17]
The answer is Earths rotation
5 0
3 years ago
) you carry a 7.0 kg bag of groceries 1.2 m above the ground at constant velocity across a 2.7 m room. how much work do you do o
lapo4ka [179]
M = 7.0 kg, the mass of the groceries
h = 1.2 m, the elevation of the bag of groceries

The bag of groceries moves a constant velocity over the 2.7-m room.
At constant velocity, there is no applied force, and the kinetic energy remains constant.

At an elevation of 1.2 m, there is an increase in PE (potential energy) given by
V = m*g*h
    = (7.0 kg)*(9.8 m/s²)*(1.2 m)
    = 82.32 J

The change in PE is equal to the work done.

Answer: 82.3 J

3 0
3 years ago
A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress
Paul [167]

Answer:

2625.156\ \text{N}

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

m_m = Mass of mattress = 4 kg

\rho = Density of water = 1000\ \text{kg/m}^3

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Volume of mattress

V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3

Weight of water displaced is equal to the buoyant force

Mass of water

m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}

Mass of person would be

m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}

Weight of the person would be

w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}

The air mattress could hold a person that weighs up to 2625.156\ \text{N}.

8 0
2 years ago
In 2013, the world record depth for free diving without assistance was 101 m. What is the pressure in the water (assumed freshwa
serg [7]

Answer:

The pressure in the water is 1.1\times10^{6}\ Pa

Explanation:

Given that,

Depth = 101 m

Let P be the pressure at the bottom of water at a depth

We need to calculate the pressure in water

Using formula of pressure

P=P_{w}+P_{atm}

Where, P_{atm} = atmospheric pressure

P_{w} = pressure in water

Put the value of P_{w} in to the formula

P=\rho hg+P_{atm}

Put the value into the formula

P=1000\times101\times9.8+101325

P=1.1\times10^{6}\ Pa

Hence, The pressure in the water is 1.1\times10^{6}\ Pa

6 0
3 years ago
Read 2 more answers
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