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aev [14]
2 years ago
11

A test charge gains 10 joules of potential energy as it moves through an electric field. It starts its movement at point 1 and e

nds its movement at point 2. The potential difference between the two points is 4 volts. How many coulombs of charge are carried by the test charge
Physics
1 answer:
Nataliya [291]2 years ago
8 0

2.5 C coulombs of charge are carried by the test charge.

<h3>What is test charge?</h3>

A test charge is a charge of such a modest size that it has little impact on the field surrounding the site where it is placed. To determine the strength and direction of an electric field, a positive test charge is a unit positive charge.

U = qV

where,

U = 10 j

V = 4V

then, q = U/V

q = 10/4

q = 2.5 C

to learn more about test charge go to - brainly.com/question/21830343

#SPJ4

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For a freely falling object dropped from rest, what is the acceleration at the
Zinaida [17]

The acceleration of the object after 3 seconds of fall is -9.8 m/s².

The given parameters;

  • initial velocity of the object, u = 0
  • time of motion of the object, t = 3 seconds

Acceleration is the change in velocity per change in time of motion.

The acceleration of the object after 3 seconds of fall is calculated as follows;

  • Since the object is in free fall, the object experiences only acceleration due to gravity.
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Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².

Learn more here: brainly.com/question/13197713

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2 years ago
A current of 17 A flows through a resistor of 10 2. What is the voltage<br> across the resistor
zhenek [66]
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2 years ago
Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

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