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aev [14]
2 years ago
11

A test charge gains 10 joules of potential energy as it moves through an electric field. It starts its movement at point 1 and e

nds its movement at point 2. The potential difference between the two points is 4 volts. How many coulombs of charge are carried by the test charge
Physics
1 answer:
Nataliya [291]2 years ago
8 0

2.5 C coulombs of charge are carried by the test charge.

<h3>What is test charge?</h3>

A test charge is a charge of such a modest size that it has little impact on the field surrounding the site where it is placed. To determine the strength and direction of an electric field, a positive test charge is a unit positive charge.

U = qV

where,

U = 10 j

V = 4V

then, q = U/V

q = 10/4

q = 2.5 C

to learn more about test charge go to - brainly.com/question/21830343

#SPJ4

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A tennis ball is dropped from a roof. If it takes 38.9 seconds to reach the ground, how fast is the ball moving just before it h
Ilya [14]

Answer:

The velocity of the ball before it hits the ground is 381.2 m/s

Explanation:

Given;

time taken to reach the ground, t = 38.9 s

The height of fall is given by;

h = ¹/₂gt²

h = ¹/₂(9.8)(38.9)²

h = 7414.73 m

The velocity of the ball before it hits the ground is given as;

v² = u² + 2gh

where;

u is the initial velocity of the on the root = 0

v is the final velocity of the ball before it hits the ground

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 7414.73 )

v = 381.2 m/s

Therefore, the velocity of the ball before it hits the ground is 381.2 m/s

5 0
2 years ago
You are designing a flywheel. It is to start from rest and then rotate with a constant angular acceleration of 0.200 rev/s^2. Th
Rama09 [41]

Answer:

 I = 8.75 kg m

Explanation:

This is a rotational movement exercise, let's start with kinetic energy

        K = ½ I w²

They tell us that K = 330 J, let's find the angular velocity with kinematics

      w² = w₀² + 2 α θ

as part of rest w₀ = 0

      w = √ 2α θ

let's reduce the revolutions to the SI system

      θ = 30.0 rev (2π rad / 1 rev) = 60π rad

let's calculate the angular velocity

      w = √(2  0.200  60π)

      w = 8.683 rad / s

we clear from the first equation

        I = 2K / w²

let's calculate

        I = 2 330 / 8,683²

        I = 8.75 kg m

4 0
3 years ago
Jin knows that the initial internal energy of a closed system is 78 J and the final internal energy is 180 J. He also knows that
lawyer [7]

As we know by the first law of thermodynamics

Q = \Delta U + W

here we know that

Q = heat given to the system

\Delta U = U_f - U_i

W = work done by the system

now here we can say

\Delta U = 180 - 78 = 102 J

W = 64 J

now we can say that heat will be given as

Q = 64 + 102 = 166 J

now here we can say that Jin does the error in his first step while calculation of change in internal energy as he had to subtract it while he added the two energy

So best describe Jin's Error is

<em>B )For step 1, he should have subtracted 78 J from 180 J to find the change in internal energy. </em>

8 0
3 years ago
Suppose that you needed to make a pen for some small animals. You have 12 m of fencing. You decide to make a circular pen, becau
Lady_Fox [76]

Answer:

1.909 m

Explanation:

Length of fence = 12 m

r = Radius of circle made by the provided fence

Cirumference of a circle is given by

C=2\pi r

The circumference of the circle will be equal to the length of the fence

2\pi r=12

\\\Rightarrow r=\dfrac{12}{2\pi}

\\\Rightarrow r=1.909\ m

The radius of the fence is 1.909 m

8 0
3 years ago
A cat jumps off a piano that is 1.3m high. The initial velocity of the cat is 3m/s at an angle of 37degrees above the horizontal
SpyIntel [72]

Answer:

x=1.75m

Explanation:

From the exercise we have that

y_{o}=1.3m\\v_{o}=3m/s, \beta  =37\\

<em><u>To find how far from the edge of the piano does the cat strike the floor, we need to calculate its time first </u></em>

y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}

At the end of the motion y=0m

0=1.3+3sin(37)t-\frac{1}{2}(9.8)t^{2}

Solving for t

t=-0.36 s or t=0.73s

Since the <u>time</u> can't be negative the answer is t=0.73

Knowing that we can calculate how far does the cat strike the floor

x=v_{ox}t=3cos(37)(0.73)=1.75m

6 0
3 years ago
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