small ball is attached to one end of a spring that has an unstrained length of 0.245 m. The spring is held by the other end, and
1 answer:
Answer:
Explanation:
As we know that the force required to move the mass in circle with uniform speed is known as centripetal force
This centripetal force is given as
while mass is revolving in horizontal circle the force is due to spring so it is given as
now we have
now when mass is suspended at the end of spring then we have
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In the first case, the force acting on the spring is the weight of the mass:
This force causes a stretching of
on the spring, so we can use these data to find the spring constant:
In the second case, the first mass is replaced with a second mass, whose weight is
And since we know the spring constant, we can calculate the new elongation of the spring:
This force causes a stretching of
In the second case, the first mass is replaced with a second mass, whose weight is
And since we know the spring constant, we can calculate the new elongation of the spring:
Answer:
Net pull = 110 N to the left
Explanation:
Group the different pulls according to the direction (right or left)
2 pull 196 N each to the right
4 pull 98 N each to the left
5 pull 62 N each to the left
3 pull 150 N each to the right
1 pull 250 N to the left
Since positive direction is to the right, the pulls to the left will have a minus (-)
The resulting force is negative, meaning the direction is to the left