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ale4655 [162]
3 years ago
6

small ball is attached to one end of a spring that has an unstrained length of 0.245 m. The spring is held by the other end, and

the ball is whirled around in a horizontal circle at a speed of 3.55 m/s. The spring remains nearly parallel to the ground during the motion and is observed to stretch by 0.0194 m. By how much would the spring stretch if it were attached to the ceiling and the ball allowed to hang straight down, motionless? Number Enter your answer in accordance to the question statement Units Choose the answer from the menu in accordance to the question statement
Physics
1 answer:
Helga [31]3 years ago
6 0

Answer:

x = 4 \times 10^{-3} m

Explanation:

As we know that the force required to move the mass in circle with uniform speed is known as centripetal force

This centripetal force is given as

F_c = \frac{mv^2}{R}

while mass is revolving in horizontal circle the force is due to spring so it is given as

F_c = kx

kx = \frac{mv^2}{R}

k(0.0194) = \frac{m\times 3.55^2}{(0.245 + 0.0194)}

k(0.0194) = 47.66 m

now we have

\frac{k}{m} = 2457

now when mass is suspended at the end of spring then we have

mg = kx

x = \frac{mg}{k}

x = \frac{9.81}{2457}

x = 4 \times 10^{-3} m

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Which of the physical variables listed below will change when you change the area of the capacitor plates (while keeping the bat
RSB [31]

Answer:

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Explanation:

Let A be the area of the capacitor plate

The capacitance of a capacitor is given as;

C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\

where;

V is the potential difference between the plates

The charge on the plates is given as;

Q = \frac{V\epsilon _0 A}{d}

The energy stored in the capacitor is given as;

E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2

Thus, the physical variables listed that will change include;

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

3 0
3 years ago
A rifle is aimed horizontally at a target 49 m away. the bullet hits the target 2.3 cm below the aim point. part a what was the
Nezavi [6.7K]

We use the equation of motion for vertical component,

s_{y} = u_{y} t+\frac{1}{2} gt^2.

Here, s_{y}   is displacement of bullet, u_{y}  is vertical initial velocity of bullet which is equal to zero because bullet was fired horizontally, and t is time of flight.

Therefore,

s_{y} =\frac{1}{2}gt^2

Given, s_{y} =2.3 \ cm = 2.3 \times 10^{-2} \ m

Substituting the values, we get time of flight

2.3 \times 10^{-2} \ m = \frac{1}{2} \times 9.8 \ m/s^2 \times t^2 \\\\ t =\sqrt{46.94 \times 10^{-4} \ s } = 0.069 \ s

4 0
3 years ago
In a thundercloud there may be an electric charge of +40 C near the top of the cloud and -40 C near the bottom of the cloud. The
Ratling [72]

Answer:

Electric force, F=-3.59\times 10^6\ N

Explanation:

Given that,

Electric charge 1, q_1=+40\ C

Electric charge 2, q_2=-40\ C

Distance, d=2\ km=2\times 10^3\ m

To find,

The electric force between these two sets of charges.

Solution,

There exists a force between two electric charges and this force is called electrostatic force. It is equal to the product of electric charged divided by square of distance between them.

F=k\dfrac{q_1q_2}{d^2}

k is the electrostatic constant

F=8.99\times 10^9\times \dfrac{40\times (-40)}{(2\times 10^3)^2}

F=-3.59\times 10^6\ N

So, the electric force between these two sets of charges is -3.59\times 10^6\ N.

5 0
3 years ago
Use absolute dating in a sentence
Scrat [10]

Answer:

scientists will use absolute dating to find how old a fossil exactly is.

4 0
2 years ago
Read 2 more answers
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shutvik [7]
The answer is 3
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