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denis23 [38]
2 years ago
12

Why does sound travel faster under water??

Physics
1 answer:
Gre4nikov [31]2 years ago
5 0
In water, the particles are much closer together, and they can quickly transmit vibration energy from one particle to the next. This means that the sound wave travels over four times faster than it would in air, but it takes a lot of energy to start the vibration.
You might be interested in
How much work in joules is required to lift a 23 kg box up from the ground to your waist that is 1.0 meters high, carry it 6 met
PSYCHO15rus [73]

Answer:

2682

Explanation:

Work done is given by :

Work = Force x distance

         =  mg x d

So, work done in lifting the box of 23 kg up to my waist of 1 m high is :

W = mg x d

   = 23 x 9.18 x 1

   = 211.14

Now work done carrying the box horizontally 6 meters across the room is

W = mg x d

   = 23 x 9.18 x 6

   = 1266.84

Work done in placing the box on the shelf that is 5.7 m above the ground is

W = mg x d

   = 23 x 9.18 x 5.7

   = 1203.49

So the total work done is = 211.14 + 1266.84 + 1203.49

                                          = 2681.47

                                          = 2682 (rounding off)

5 0
2 years ago
How does the period affects the centripetal force?
Anna71 [15]

Answer:According to the Equation (2), centripetal force is proportional to the square of the speed for an object of given mass M rotating in a given radius R.

Explanation:The Period T. The time T required for one complete revolution is called the period. For. constant speed. v = 2π r T holds.

8 0
3 years ago
Read 2 more answers
Two nuclei join to form a larger nucleus during which process
pentagon [3]

nuclear fusion- produces huge amounts of energy.

4 0
3 years ago
Read 2 more answers
An ac generator has a maximum emf output of 150 V. What is the rms current in the circuit when the generator is connected to a 3
natima [27]

This is an insidious question.  Quite frankly, I would not have
expected to see it here on Brainly.  But I'm ready to play the
cards that you have dealt me.

None of the choices offered is a correct solution.

If the output of the AC generator is nice and sinusoidal, and
its maximum (peak) emf is 150 volts, then its RMS emf is

                             (1/2) (150) (√2)  =  106.07 volts.

The resistor's dissipation is   

                             Power = (current) x (voltage) .

If the resistor is dissipating its full rated 35W, then

                       35W  =  (current) x (106.07 V)

Divide each side by 106.07 V:   

           RMS Current =  (35W) / (106.07 V)  =  0.33 Ampere .
_________________________________________

Looking over the choices offered . . . 

The largest choice ... 3.1 A ... is the current in a resistor
that is dissipating 35W if the voltage is

                           (35W / 3.1A)  =  11.29 volts .

The smallest choice ... 1.2 A ... is the current in a resistor
that is dissipating 35W if the voltage is

                           (35W / 1.2A)  =  29.17 volts .

Whatever you meant the so-called "150 V" of the generator
to represent ... whether the RMS sinusoidal, peak sinusoidal,
peak square-wave, RMS square-wave, DC, average, etc. ...
none of the choices for current, in combination with any of these
generators, would dissipate 35W.

3 0
3 years ago
Identify the charge(s) with increasing electric potential energy.
kap26 [50]
Cznxjsjssbsishsisbsisbsisbsbeoeb
4 0
3 years ago
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