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katrin2010 [14]
3 years ago
12

Should young children be treated as “little adults”? Based on what you have learned about development, do you think that is reas

onable? Why or why not?
Physics
2 answers:
belka [17]3 years ago
7 0

Since I’m not sure what you have been learning about child development I will just answer with my personal opinion. I hope my answer can be of help.



I personally think children definitely should not be treated as young adults. It is important for young children to experience that period of innocence and immaturity. Without this they will be deprived from having other relationships with children their age because they will not get along with them since they are more mature than others. This could cause them to ultimately distance themselves from others and have poor social skills. Children can not be treated as a adults after all they just came into this world! Treating a child like this could leave them depressed or mad when they get older. This is because they can never look back and laugh at their own silly but funny mistakes. Or remember having childish fun with friends or family. This may not be important but it will severely affect the child when he/she becomes older. Young children also go through important stages of their life. If we are to treat our children like they are adults they will not go through these stages and will not develop practical skills they will need in life. This can also be very dangerous because this could cause a child to detach themselves from their parents. It is EXTREMELY important for kids to be able to attach themselves to their parent and start to learn or mimic their behavior. If you treat them as if they are an adult they could detach from you because they feel a lack of love or sensitivity from you.
saul85 [17]3 years ago
6 0

Answer:

maybe if you posted a picture of the story i can help you

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For a complete vector quantity, what information needs to be given?
zhenek [66]

The magnitude of the quantity and its direction.

4 0
3 years ago
In part B of the lab, when the current flows through the orange part of the wire from right to left, the wire deflects (or moves
s2008m [1.1K]

Answer:

This seems to be incomplete, as we do not have any information about the magnetic field surrounding the wire, but we can answer in a general way.

We know that for a wire of length L, with a current I, and in a magnetic field B, the force can be written as:

F = L*(IxB)

if we define the right as the positive x-axis, and knowing that the current flows to the right, we can write:

I = i*(1, 0, 0)

And the field will be some random vector that can't be parallel to the current because in that case, we do not have any force.

To find the direction of the force, which will tell us the direction in which the wire deflects or moves, first, we need to point with our thumb in the direction of the current, in this case, to the right.

Now, with the hand open, using the tip of our other fingers we point in the direction of the magnetic field.

For example, if the magnetic field is in the positive z-axis, we will point upwards.

Now the palm of our hand tells us in which direction the force is applied.

This is the right-hand rule.

For example, in the case that the current goes to the right and the magnetic field is upwards, we could see that the force is to the front.

7 0
3 years ago
The frequency of a person's pendulum is 0.3204 Hz when at a location where g is known to be exactly 9.800 m/s^2.
wel

Answer:

A) g = 9.751 m/s², B)       h = 2.573 10⁴ m

Explanation:

The angular velocity of a pendulum is

           w = √ g / L

Angular velocity and frequency are related.

          w = 2π f

          f = 1 / 2π √ g / L

A) with the initial data we can look for the pendulum length

        L = 1 /4π²   g / f²

        L = 1 /4π²   9,800 / 0.3204²

        L = 2.4181 m

The length of the pendulum does not change, let's look for the value of g for the new location

        g = 4π² f²  L

        g = 4π² 0.3196²  2.4181

        g = 9.75096 m / s²

         g = 9.751 m/s²

B) The value of the acceleration of gravity can be found with the law of universal gravitation

           F = G m M / R_{e}²

And Newton's second law

           W = m g

           W = F

         G m M / R_{e}² = mg

         g = G M / R_{e}²

         R_{e}² = G M / g

Let's calculate

          R_{e}² = 6.67 10⁻¹¹ 5.98 10²⁴ /9.75096

          R = √ 4.0905 10¹³ = √ 40.9053 10¹²

          R = 6.395726 10⁶ m

The height above sea level is

         h = R - [tex]R_{e}[/tex

         h = (6.395726 -6.37) 10⁶

         h = 0.0257256 106

         h = 2.573 10⁴ m

7 0
3 years ago
A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?
antiseptic1488 [7]
Using p = mv 3 = 1× v v = 3m/s
6 0
3 years ago
a toy propeller fan with a moment of inertia of .034 kg x m^2 has a net torque of .11Nxm applied to it. what angular acceleratio
Harman [31]

Answer:

The  angular acceleration is  \alpha  = 3.235 \ rad/s ^2

Explanation:

From the question we are told that

    The moment of inertia is  I  =  0.034\ kg \cdot m^2

     The  net torque is  \tau  =  0.11\ N \cdot m

Generally the net torque is mathematically represented as

           \tau =  I  *  \alpha

Where \alpha is the angular acceleration so  

        \alpha  =  \frac{\tau }{I}

substituting values

         \alpha  =  \frac{0.1 1}{ 0.034}

        \alpha  = 3.235 \ rad/s ^2

6 0
3 years ago
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