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4 years ago

What are ATP and NADPH used for by the cell?

Biology

1 answer:

aksik [14]4 years ago

8 0

The electrons that freed from the water are transferred to ATP and NADPH. ... In these reactions, the energy from ATP and NADPH is used to fix carbon dioxide (CO2). The products of this reaction are sugar molecules and various other organic molecules necessary for cell function and metabolism.

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PLEASE HELP. ITS FOR MY SIS. PLEASE NUMBER EACH ANSWER FOR NO CONFUSION.

Oksi-84 [34.3K]

Answer:

1. It provides not a lot of energy due to its lack of protein

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3. Fibers keep your digestive system clean and healthy, easing bowel movements, and flushing cholesterol and harmful carcinogens out of the body.

4. It is considered a nutrient because it plays a vital role in keeping alive

Explanation:

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3 years ago

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Yeast cells, plant cells, and mammal cells all share many similarities in cell signaling. This provides evidence that:________

alina1380 [7]

Answer:

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3 years ago

When elements and components that are dissolved in water leave a solution what is the result

rosijanka [135]

Answer:

-A solution is a mixture in which one substance is dissolved in another. When elements and compounds that are dissolved in water leave a solution, crystallization occurs.

Explanation:

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4 years ago

Solar energy is a clean, renewable energy source. Once a solar plant is built there is no fuel cost only maintenance. Why does s

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3 years ago

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Example 1: Two different enzymes are able to catalyze the same reaction, A → B. They both have the same Vmax, but differ their K

luda_lava [24]

Answer: (a) = 0.022mmoles/minute; (b) = 0.00022mmoles/minute; (c) = 0.022mmoles/minute

Explanation:

The Michaelis- Menten equation is used to show the relationship between substrate concentration and reaction rate.

The equation is Vo = Vmax[S]/(Km + [S]

where Vo is the initial velocity, Vmax is the maximum velocity, [S] is the substrate concentration, Km is the Michaelis constant.

(a) For enzyme 1; Vo = 0.002mmoles/minute, Vmax = ?, [S] = 0.1mM, Km =1.0mM; making Vmax subject of the formula;

Vmax = Vo * (Km + [S])/ [S]

Vmax = 0.002*(1.0 + 0.1)/ 0.1

Vmax = 0.022mmoles/minute (Vmax for Enzyme 1&2)

(b) Vo = Vmax[S]/(Km + [S]

Vo = 0.022 * 0.1/(10+0.1) = 0.00022mmoles/minute

Vo = 0.022*1000/(1.0+1000) = 0.022mmoles/minute

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4 years ago