Answer:
There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1432
p = 23% = 0.23
Alpha, α = 0.05
Number of theft complaints , x = 321
First, we design the null and the alternate hypothesis
This is a one-tailed test.
Formula:
Putting the values, we get,
Now, we calculate the p-value from the table.
P-value = 0.298
Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.
Conclusion:
Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.
Y = 2x + 1
y = 2(-1) + 1
y= -2 + 1
y= -1
I need a picture I will answer the question if there is a picture
Answer:
<em>The first step is to determine the average
</em>

<em>The exercise says it’s a normal distribution: (n=8)</em>

<em>According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained
</em>
<em />

<em>The variable t has 7 grade to liberty, we calculate the p-value as:
</em>

This value is very high, therefore the hypothesis is not rejected