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KengaRu [80]
3 years ago
14

Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45 m diamete

r semicircles. A greyhound can run around these turns at a constant speed of 16 m/s .What is its acceleration in m/s^2?What is its acceleration in units of g?
Physics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

a=1.161 g

Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

a=\frac{v^2}{r}

where:

v is the speed

r is the radius

Now,

a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2

In g units:

a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g

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