1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dlinn [17]
3 years ago
12

The wind pushes a paper cub along the sand at a beach. The cup has a mass of 25 grams (= ? Kg's) and accelerates at a rate of 5

m/s/s. How much force (in Newtons) is the wind exerting on the cup
Physics
1 answer:
bixtya [17]3 years ago
7 0

Force = (mass) x (acceleration)

= (0.025 kg) x (5 m/s²)

=   0.125 Newton
You might be interested in
According to Newton's law of motion, when we shake a mango tree, mangoes fall down explain.​
Reptile [31]
When we shake a mango tree, the mangoes fall down. It is because when we shake the tree, the mango tend to be rest due to inertia where as the branches are in motion. That is why the mangoes tend to be at rest due to inertia where as the branches are in the motion.
8 0
2 years ago
Three point charges are arranged along the x-axis. Charge q1 = +3.00 uC is at the origin, and charge q2= -5.00 uC is at x= 0.200
artcher [175]
We have all the charges for q1, q2, and q3. 
Since k = 8.988x10^2, and N=m^2/c^2

F(1) = F (2on1) + F (3on1)

F(2on1) = k |q1 q2| / r(the distance between the two)^2
k^ | 3x10^-6 x -5 x 10^-6 |   / (.2m)^2
F(2on1) = 3.37 N

Since F1 is 7N,

F(1) = F (2on1) + F (3on1)
7N = 3.37 N + F (3on1)

Since it wil be going in the negative direction,
-7N = 3.37 N + F (3on1)
F(3on1) = -10.37N

F(3on1) = k |q1 q3| / r(the distance between the two)^2 
r^2 x F(3on1) = k |q1 q3| 
r = sqrt of k |q1 q3| / F(3on1) 
= .144 m (distance between q1 and q3)
0 - .144m 

So it's located in -.144m

Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
6 0
3 years ago
Read 2 more answers
Which of the following units are fundamental units in the S.I. system of measurement
Nataliya [291]
Is recommend attaching the answer choices; Meters, Liters, Grams are three basic ones
8 0
3 years ago
Read 2 more answers
How many Joules of potential
s2008m [1.1K]

Answer:

40 j, 80j.

Explanation:

P.E= mgh. G=10 m/s².

For 4m, P.E=1*10*4=40 joules.

For 8m, P.E=1*10*8=80 joules.

4 0
3 years ago
Which elements will bond ionically with barium such that the formula would be written as BaX2? A) Nitrogen, chlorine, and sodium
erma4kov [3.2K]

The answer would be:

B. Chlorine, iodine and Fluorine

Barium has 2 valence electrons. To satisfy the BaX₂ , this would mean that Barium will need to give one of each of its electrons. The elements that need 1 electron would be those that have 7 valence electrons to complete the octet. These elements would fall in group 7 or halogens. Chlorine, iodine and fluorine are all in Group 7, so this would be the best choice.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Work in the amount of 280 J is done in lifting an object a distance of 4.0 m in a time. How much force did it take to lift the o
    6·1 answer
  • Select the correct answer from each drop-down menu.
    9·2 answers
  • how do you find the uncertainty of a single measurement? For example, I am trying to find the uncertainty of 26 grams. ​
    7·1 answer
  • 25 PTS
    12·1 answer
  • A circuit was set up as shown in the diagram . The tgree resistors are identical
    10·1 answer
  • What is a non example of atmosphere
    12·2 answers
  • A solar-powered car is traveling at constant speed around a circular track. what happens to the centripetal acceleration of the
    7·1 answer
  • Examine the words and/or phrases below and determine the relationship among the majority of words/phrases. Choose the option tha
    12·1 answer
  • The vectors of the magnetic field around a long, straight, current-carrying wire are:
    10·2 answers
  • What do fluorine, sodium, and aluminum have in common
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!