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dlinn [17]
3 years ago
12

The wind pushes a paper cub along the sand at a beach. The cup has a mass of 25 grams (= ? Kg's) and accelerates at a rate of 5

m/s/s. How much force (in Newtons) is the wind exerting on the cup
Physics
1 answer:
bixtya [17]3 years ago
7 0

Force = (mass) x (acceleration)

= (0.025 kg) x (5 m/s²)

=   0.125 Newton
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A series RLC circuit consists of a 52.0 Ω resistor, a 4.80 mH inductor, and a 330 nF capacitor. It is connected to an oscillator
Tju [1.3M]

Answer:

(G) 75.11 ohm

(H) 0.08 A

(I) 46.2 degree

Explanation:

R = 52 ohm

L = 4.8 m H = 4.8 x 106-3 H

C = 330 nF = 330 x 10^-9 F

Vo = 6 V

(G)

f = 5000 Hz

Let the impedance is Z.

X_{L}= 2 \pi fL = 2 \times 3.14\times 5000\times 4.8\times 10^{-3}=150.72 ohm

X_{c}= \frac{1}{2 \pi fC}=\frac{1}{2\times 3.14\times 5000\times 330\times 10^{-9}}=96.51 ohm

Z=\sqrt{R^{2}+\left ( X_{L}-X_{c} \right )^{2}}

Z=\sqrt{52^{2}+\left (150.72-96.51)^{2}}=75.11 ohm

(H) Let Io be the peak current

I_{0}=\frac{V_{0}}{Z}=\frac{6}{75.11}=0.0798 A = 0.08 A

(I) Let Ф be the phase angle

tan\phi = \frac{X_{L}-X_{C}}{R}

tan\phi =\frac{150.72-96.51}}{52}=1.0425

Ф = 46.2 degree

4 0
3 years ago
Sound cannot travel through a vacuum. Explain why.
asambeis [7]

Answer:

A vacuum is an area without any air, like space. So sound cannot travel through space because there is no matter for the vibrations to work on it.

3 0
3 years ago
A force of 6 N acts on a 33 kg object for 9 seconds. What is the objects change in velocity?
GuDViN [60]
Acceleration = change in velocity/time
By F = ma,
6 = 33 x change in velocity / 9
change in velocity = +1.636 m/s
4 0
3 years ago
8) A plastic rod, initially uncharged, is rubbed with wool and obtains a charge of 10 C. What is the charge on the wool after ru
LenKa [72]

Answer:

The charge on the wool after rubbing is - 10 C

Explanation:

Every uncharged body is electrically neutral, if the plastic rod acquires 10 Coulombs of charge after been rubbed with wool, then the wool will be left with an equal but opposite charge. This shows that the initial charge on the wool is 10 protons and 10 electrons and when the plastic acquires 10 C (10 protons), the wool will be left with excess 10 electrons.

Therefore, the charge on the wool after rubbing is - 10 C (negative 10 Coulombs).

6 0
4 years ago
A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65
Sedaia [141]

The thermal energy was produced is 116J

<h3>What is the thermal energy produced?</h3>

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff =  0.65 *  5.0 kg * 9.8 m/s^2 * cos 25

Ff = 29 N

Hence, the thermal energy is;

29 N * 4.0 m = 116J

Learn more about frictional force:brainly.com/question/1714663

#SPJ1

4 0
2 years ago
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