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PIT_PIT [208]
3 years ago
9

5

Physics
1 answer:
joja [24]3 years ago
3 0

Answer:

Electrical force is directly proportional to the product of the charges on the two objects.

Explanation:

The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{d^2}

Where

k is electrostatic constant

q₁ and q₂ are charges

d is the distance between charges

It can be very clear that the electric force is directly proportional to the product of charges and inversely proportional to the square of the distance between them.

Hence, the correct option is (a) "Electrical force is directly proportional to the product of the charges on the two objects".

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determine which will change if you turn up a radio’s volume: wave velocity, intensity, pitch, frequency, wavelength, loudness.
Mamont248 [21]
I think wavelength because the radios volume is being turned up.

5 0
3 years ago
b) The distance of the red supergiant Betelgeuse is approximately 427 light years. If it were to explode as a supernova, it woul
Nat2105 [25]

Answer:

b) Betelgeuse would be \approx 1.43 \cdot 10^{6} times brighter than Sirius

c) Since Betelgeuse brightness from Earth compared to the Sun is \approx 1.37 \cdot 10^{-5} } the statement saying that it would be like a second Sun is incorrect

Explanation:

The start brightness is related to it luminosity thought the following equation:

B = \displaystyle{\frac{L}{4\pi d^2}} (1)

where B is the brightness, L is the star luminosity and d, the distance from the star to the point where the brightness is calculated (measured). Thus:

b) B_{Betelgeuse} = \displaystyle{\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2}} and B_{Sirius} = \displaystyle{\frac{26L_{Sun}}{4\pi (26\ ly)^2}} where L_{Sun} is the Sun luminosity (3.9 x 10^{26} W) but we don't need to know this value for solving the problem. ly is light years.

Finding the ratio between the two brightness we get:

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sirius}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (26\ ly)^2}{26L_{Sun}} \approx 1.43 \cdot 10^{6} }

c) we can do the same as in b) but we need to know the distance from the Sun to the Earth, which is 1.581 \cdot 10^{-5}\ ly. Then

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sun}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (1.581\cdot 10^{-5}\ ly)^2}{1\ L_{Sun}} \approx 1.37 \cdot 10^{-5} }

Notice that since the star luminosities are given with respect to the Sun luminosity we don't need to use any value a simple states the Sun luminosity as the unit, i.e 1. From this result, it is clear that when Betelgeuse explodes it won't be like having a second Sun, it brightness will be 5 orders of magnitude smaller that our Sun brightness.

4 0
3 years ago
Samuel throws a ball into the air 20 meters. It reaches the top of its flight at 2
EastWind [94]

Answer:

10 m/s

Explanation:

7 0
3 years ago
Read 2 more answers
A thin rod of length 1.4 m and mass 180 g is suspended freely from one end. It is pulled to one side and then allowed to swing l
prisoha [69]

Answer:

K.E = 0.1905 J

Explanation:

From the question we are told that:

Length L=1.4m

Mass m=180g

Angular Velocity \omega=1.80rads/s

Generally the equation for Kinetic energy K.E is mathematically given by

 K.E =0.5 (1/3 ML^2 )w^2

 K.E =0.5 ( 1/3 * 0.18 * 1.4^2 ) 1.8^2

 K.E = 0.1905 J

5 0
3 years ago
Thanks + BRAINLIST <br><br> Please need correct answer asappp
garik1379 [7]
(A) Standing waves are created by two identical waves reflecting off each other

(B) a general definition of a wave interference is, when more than on wave meet and interact in the same medium

Hope this helps :)
3 0
3 years ago
Read 2 more answers
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