I don’t think we can answer this question with the information given. ANY ball thrown with ANY initial velocity v will be observed at a height h twice and with a time interval Δt.
The focal length (in meters) of a lens whose radius of curvature is 9. 2 m and has a refractive index 1.2 will be 18.4 m
The focal length of a lens is determined when the lens is focused at infinity. Lens focal length tells us the angle of view—how much of the scene will be captured—and the magnification—how large individual elements will be.
Focal length of a lens is the distance between center of lens and focal point . Focal point is a point on principal axis , at which light rays parallel to principal axis meet after refraction through lens or seem to meet after refraction .
The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature. The sign convention for focal length and radius of curvature is the same.
focal length = 2 * radius of curvature
given
radius of curvature = 9.2 m
focal length = 2 * 9.2
= 18.4 m
To learn more about focal length here
brainly.com/question/16188698
#SPJ4
The answer is C) the density of the rock
Density of rock is the dependent variable, because it depends on the temperature. The temperature can’t be the dependent variable because ,the density of a rock does not have magical powers that can change temperature of a room. However changing the temperature of the room ,will change the density of the rock. Hope this helps !
Answer:
Explanation:
Speed = Distance / Time
So, to find distance, we actually divide distance by rime.
To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,
Here,
= Wavelength
= Angle when occurs the interference point of destructive interference
Our values are given as,
Using the previous expression we have,
Therefore the distance between the two openings is 
