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slamgirl [31]
3 years ago
10

Consider the following hypothetical subject performing the EMG laboratory: Immediately after the subject's maximum grip strength

for the non-dominant arm is determined to be 16 kg, to what force will the subject squeeze next?
Physics
1 answer:
AnnZ [28]3 years ago
3 0

Answer:

The assessment of the muscles' health and the motor neurons <em>(the nerve cells controlling the muscles)</em> is determined by the procedure called Electromyography aka EMG, which identifyes nerves/muscles issues and also the quality of the signal transmission between them; like when the units in a contraction increase, correlates with the increase in the force of contraction. In this particular case of the EMG lab, the subject will squeeze to <em>1kg</em> of force.

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Answer:

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(b). The speed of the block after collision 1.11 m/s.

Explanation:

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The initial speed of the block u_{2}=0

(a). We need to calculate the speed of the ball after collision

Using formula of collision

v_{1}=(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{1}+(\dfrac{2m_{2}}{m_{1}+m_{2}})u_{2}

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Negative sign shows the opposite direction of initial direction.

(b). We need to calculate the speed of the block after collision

Using formula of collision

v_{2}=(\dfrac{2m_{1}}{m_{1}+m_{2}})u_{1}+(\dfrac{m_{1}-m_{2}}{m_{1}+m_{2}})u_{2}

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v_{2}=(\dfrac{2\times0.5}{0.5+2.30})\times3.13+0

v_{2}=1.11\ m/s

Hence, (a). The speed of the ball after collision is 2.01 m/s.

(b). The speed of the block after collision 1.11 m/s.

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