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Kipish [7]
4 years ago
10

While out hiking, you and your buddy decide to have some fun with the rocks laying all around. While sitting on a high cliff, ov

erlooking a lake, you each drop a rock into the water.
Describe the change in motion of the rock as it enters the water.
Physics
1 answer:
Ulleksa [173]4 years ago
8 0

When we drop the stone in air then during its motion in air the net force on the stone is due to gravity

so its net force is given as

F = mg

here we know that

ma = mg

so we have

a = g

now as soon as it will enter into the water then it will have resistive force due to water as well as buoyant force due to water on it in opposite direction

so the net force on the stone will decrease

so as soon as it will enter into the water the acceleration of stone will decrease due to which the rate of increase in speed of the stone will decrease as it will enter into the water

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vertical! or in other words, up!


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3 years ago
What are generated at transform fault plate boundaries?
tankabanditka [31]

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5 0
3 years ago
Zoe is shown two mystery boxes that are both 8,000cm3. Her teacher tells her that one mystery box is filled with rocks and the o
krek1111 [17]

Answer:

The box of rocks will have depression which can be seen without touching the box.

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5 0
3 years ago
Suppose a capacitor is fully charged by a battery and then disconnected from the battery. The positive plate has a charge +q and
dimaraw [331]

Answer:-q

Explanation:

Given

Capacitor is charged to a battery and capacitor acquired a charge of q i.e.

+q on Positive Plate and -q on negative Plate.

If the plate area is doubled and the plate separation is reduced to half its initial separation then capacitor becomes four times of initial value because capacitor is given by

c=\epsilon_0 \cdot \frac{A}{d}

where A=area of capacitor plate

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This change in capacitance changes the Potential such that new charge on the negative plate will remain same -q

8 0
3 years ago
*PHYSICS HELP*
sveta [45]
My calculator is about 1cm thick, 7cm wide, and 13cm long.

Its volume is (length) (width) (thick) = (13 x 7 x 1) = 91 cm³ .

The question wants me to assume that the density of my calculator
is about  the same as the density of water.  That doesn't seem right
to me.  I could check it easily.  All I have to do is put my calculator
into water, watch to see if sinks or floats, and how enthusiastically. 
I won't do that.  I'll accept the assumption.

If its density is actually 1 g/cm³, then its mass is about 91 grams.

The choices of answers confused me at first, until I realized that
the choices are actually 1g, 10² g, 10⁴ g, and 10⁶ g.

My result of 91 grams is about 100 grams ... about 10² grams.

Your results could be different.
3 0
3 years ago
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