If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).
Answer:
The metal will have changed temperature more than the water.
Explanation:
As we know that when two objects are mixed at different temperature then due to heat exchange between the two they both reach to same final temperature
This is known as thermal equilibrium
So here we have
Heat given by metal = heat absorbed by water
so we have
since mass of metal is same as that of water
so we have
so here we know that
so temperature change in water must be smaller than that of metal
The humerus<span> is the only bone of the upper arm. It is a long, large bone that extends from the scapula of the shoulder to the </span>ulna<span> and radius of the lower arm. The proximal end of the </span>humerus<span>, known as the head, is a round structure that forms the ball of the ball-and-socket shoulder joint.
</span>I just got it from google normaly i would simplify it but its to simple for me to simplify again hope this helps
Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?
Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.
(a) What is the electric potential at point a due to q1 and q2?
(b) What is the electric potential at point b?
(c) A point charge q3 = -6.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2?
Answer:
a) the potential is zero at the center .
Explanation:
a) since the two equal-magnitude and oppositely charged particles are equidistant
b)(b) Electric potential at point b, v = Σ kQ/r
r = 5cm = 0.05m
k = 8.99*10^9 N·m²/C²
Q = -2 microcoulomb
v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m
v = -105 324 V
c)workdone = charge * potential
work = -6.00µC * -105324V
work = 0.632 J
Answer:
i think it is 40 kilometers in the positive direction... if not im sorry
Explanation:
