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Agata [3.3K]
3 years ago
12

6

Physics
1 answer:
asambeis [7]3 years ago
6 0

Answer:

TAJUK

Explanation:

Sebab saya suka makan ayam goreng, esok saya nak pesan daripada kedai pak abu, terima kasih bosku

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Which components of static electricity does a photocopier use?
Salsk061 [2.6K]

Answer:

For a photocopier to work, a field of positive charges must be generated on the surface of both the drum and the copy paper. These tasks are accomplished by the corona wires. These wires are subjected to a high voltage, which they subsequently transfer to the drum and paper in the form of static electricity.

8 0
2 years ago
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?​
telo118 [61]
  • Force=12N
  • Work=9J

\\ \sf\longmapsto W=Fd

\\ \sf\longmapsto d=\dfrac{W}{F}

\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m

6 0
3 years ago
Read 2 more answers
A projectile is to be launched at an angle of 30° so that it falls beyond the pond of length 20 meters as shown in the figure.
marin [14]

Answer: A

Explanation:

I want my points so yea

4 0
2 years ago
Water in a tank which is positioned 5 feet above the ground is _____ potential energy? (answers would be like thermal, electric,
LUCKY_DIMON [66]

Answer:

Mechanical

Explanation:

The tank is at rest. And energy of any substance at rest is known as potential energy.

Now, in forms of energy, potential energy is a type of mechanical energy.

Thus, the correct option is mechanical Energy.

8 0
3 years ago
I really need help please just answer at least one
yuradex [85]

Answer:

9) a = 25 [m/s^2], t = 4 [s]

10) a = 0.0875 [m/s^2], t = 34.3 [s]

11) t = 32 [s]

Explanation:

To solve this problem we must use kinematics equations. In this way we have:

9)

a)

v_{f}^{2} = v_{i}^{2}-(2*a*x)\\

where:

Vf = final velocity = 0

Vi = initial velocity = 100 [m/s]

a = acceleration [m/s^2]

x = distance = 200 [m]

Note: the final speed is zero, as the car stops completely when it stops. The negative sign of the equation means that the car loses speed or slows down as it stops.

0 = (100)^2 - (2*a*200)

a = 25 [m/s^2]

b)

Now using the following equation:

v_{f} =v_{i} - (a*t)

0 = 100 - (25*t)

t = 4 [s]

10)

a)

To solve this problem we must use kinematics equations. In this way we have:

v_{f} ^{2} =  v_{i} ^{2} + 2*a*(x-x_{o})

Note:  The positive sign of the equation means that the car increases his speed.

5^2 = 2^2 + 2*a*(125 - 5)

25 - 4 = 2*a* (120)

a = 0.0875 [m/s^2]

b)

Now using the following equation:

v_{f}= v_{i}+a*t\\

5 = 2 + 0.0875*t

3 = 0.0875*t

t = 34.3 [s]

11)

To solve this problem we must use kinematics equations. In this way we have:

v_{f} ^{2} =  v_{i} ^{2} + 2*a*(x-x_{o})

10^2 = 2^2 + 2*a*(200 - 10)

100 - 4 = 2*a* (190)

a = 0.25 [m/s^2]

Now using the following equation:

v_{f}= v_{i}+a*t\\

10 = 2 + 0.25*t

8 = 0.25*t

t = 32 [s]

4 0
3 years ago
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