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Gemiola [76]
3 years ago
11

45 Three samples of the same solution are tested, each with a different indicator. All three indicators, bromthymol blue, bromcr

esol green, and thymol blue, appear blue if the pH of the solution is
(1) 4.7 (2) 6.0 (3) 7.8 (4) 9.9
Chemistry
2 answers:
zalisa [80]3 years ago
6 0
(4) 9.9 is the most sensible answer.

When an indicator appears blue, that means the solution is basic and the pH of the solution should be within the range of 8 and 14.

Hope this helps~


ANEK [815]3 years ago
3 0

<u>Answer:</u> The correct answer is Option 4.

<u>Explanation:</u>

Bromothymol blue, Bromocresol green and Thymol blue are the indicators which change their color according to the change in pH of the solution.

The pH range and color change of these indicators are:

  1. Bromothymol Blue: The pH range for this indicator is 6.0 to 7.5 and color change is from yellow to blue. It appears yellow below pH 6.0 and blue above pH 7.5
  2. Bromocresol green: The pH range for this indicator is 3.5 to 6.0 and color change is from yellow to blue. It appears yellow below pH 3.5 and blue above pH 6.0
  3. Thymol Blue: The pH range for this indicator is 8.0 to 9.6 and color change is from yellow to blue. It appears yellow below pH 8.0 and blue above pH 9.6

As, the highest pH of all the indicators is 9.6, so every indicator will appear blue above pH 9.6.

Hence, the correct answer is Option 4.

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A 2.4 L balloon holds 3.7 mol He. If 1.6 mol He are added to the balloon, what is the new volume?
Elanso [62]
For this question, lets apply Avagadro's law
when Pressure and temperature are constant, the volume occupied is directly proportional to the number of moles of gases.
\frac{V}{n} = k
where V-volume, n-number of moles and k - constant 
Therefore at 2 instances 
\frac{V1}{n1} =  \frac{V2}{n2}
where V1 and n1 are for 1st instance 
and V2 and n2 are for 2nd instance 
therefore 
\frac{V1}{n1} = \frac{V2}{n2}
V1 = 2.4 L
n1 = 3.7 mol
n2 = 3.7 + 1.6 = 5.3 mol
since more He moles are added at the 2nd instance its the sum of the moles.
V2 needs to be calculated \frac{2.4}{3.7}  = \frac{V2}{5.3}
V2 = 2.4 x 5.3 / 3.7
     = 3.4 L
Answer is 1st option 3.4 L


6 0
3 years ago
7. Which of the following pairs of elements is most likely to form an ionic
yaroslaw [1]

Answer:

not sure if this us right but oxygen and fluorine? I learned chem but I forgot about it kinda sorry

5 0
3 years ago
Explain why a random copolymer is obtained when 3,3-dimethyl-1-butene undergoes cationic polymerization.
dezoksy [38]

Solution :

In the field of chemistry, the cationic polymerization is a kind of the chain growth polymerization where the cation initiator transfers the charge to the monomer and makes it more reactive. This kind of polymerization reaction is very sensitive to the temperature. With increase in temperature, the molecular weight as well as the reaction rate decreases rapidly.

Thus in the cationic polymerization of the 3,3-dimethyl-1-butene, the carbonation intermediate is formed and it rearranges itself. The attack o the 2nd alkene ca take place both the carbonations, so that random copolymer is formed.

8 0
2 years ago
Describe the chemical reaction based on the chemical equation below also whether the equation is balanced
Crank

Answer:

Its not balanced

4NH₃ + 7O₂ ⇒ 4NO + 6H₂O

3 0
3 years ago
Enter your answer in the provided box. Consider the reaction: N2(g) + 3H2(g) → 2NH3(g) Suppose that a particular moment during t
Mashcka [7]

Answer:

0.0253 M/s

Explanation:

From the reaction

N₂ + 3H₂ → 2NH₃

The rate of reaction can be written as

Rate = - \frac{d[N_2]}{dt} = - \frac{1}{3} \frac{d[H_2]}{dt} = + \frac{1}{2} \frac{d[NH_3]}{dt}

From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,

So,

Rate of reaction of molecular nitrogen = \frac{1}{3} \times 0.0759

Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s

4 0
3 years ago
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