This question is describing the following chemical reaction at equilibrium:
And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:
Thus, by recalling the Van't Hoff's equation, we can write:
Hence, we solve for the enthalpy change as follows:
Finally, we plug in the numbers to obtain:
![\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Cfrac%7B-8.314%5Cfrac%7BJ%7D%7Bmol%2AK%7D%20%2Aln%280.25%2F9%29%7D%7B%5B%5Cfrac%7B1%7D%7B%2875%2B273.15%29K%7D%20-%5Cfrac%7B1%7D%7B%2825%2B273.15%29K%7D%20%5D%20%7D%20%5C%5C%5C%5C%5C%5C%5CDelta%20H%3D4%2C785.1%5Cfrac%7BJ%7D%7Bmol%7D)
Learn more:
Organic is safer inorganic is the same but less better
Answer:
The overall speed add then divide
Hope this helped :)
In 1 molecule of the compound C₆H₁₂O₂ there are 12 moles of hydrogen atoms
<h3>Further explanation</h3>
Given
C₆H₁₂O₂ compound
Required
moles of Hydrogen
Solution
In a compound, there is a mole ratio of the constituent elements.
The empirical formula is the smallest comparison of atoms of compound forming elements.
A molecular formula is a formula that shows the number of atomic elements that make up a compound.
In the C₆H₁₂O₂ compound, there are 3 forming elements: C, H and O
The number of each element is indicated by its subscript
C: 6 moles
H = 12 moles
O = 2 moles
With standard pressure there is a set list of values. (at STP), most common is 760torr. So whenever you see "at STP" or "at standard temperature pressure" you will use 760torr for pressure. Same thing goes with temperature, if you're not given temp and it says at STP you will use 273K.
For this problem:
You will be using the combined gas law:
(Pressure 1) x (Volume 1) / (Temp. 1) = (Pressure 2) x (Volume 2) / (Temp. 2)
(760torr) x (5.63L) / (287K) = (?) (9.21L) / (287K)
Pressure 2 = 465torr
*Hope this clarifies STP for you! :)
