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forsale [732]
3 years ago
14

Calculate the ph and the poh of an aqueous solution that is 0.030 m in hcl(aq) and 0.070 m in hbr(aq) at 25°c.

Chemistry
1 answer:
pickupchik [31]3 years ago
7 0

Solution:

Since, both are strong acids. So both ionize 100% in solution.  

Let us consider that we have 1 liter of the solution. In it, we have 0.030 moles of H+ (from the HCl) and 0.070 moles of H+ (from the HBr) for a total of 0.100 mole in 1 liter. Here we ignore the chloride ion and the bromide ion since both acids ionize 100%. The only important ion (for pH) is the H+.  

In terms of just the H+, this is 0.100 M  

pH = - log 0.100 = 1.000  

And

pH + pOH = 14.000  

-1.000+14.000=13.000

Therefore,

pOH = 13.000


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\boxed {\tt mass=29.25 \ grams}

Explanation:

The density formula is mass over volume.

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Rearrange the formula for the mass, m. Multiply both sides of the formula by v.

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Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.

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d= 0.65 \ g/mL\\v= 45 \ mL

Substitute the values into the formula.

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Multiply. Note the milliliters, or mL will cancel out.

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