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abruzzese [7]
3 years ago
12

What information about an element is most crucial for locating that element in the periodic table?

Physics
1 answer:
castortr0y [4]3 years ago
4 0
The most crucial information would be its atomic number. 
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An airplane refuels in Bakersfield and continues on to Fresno. It travels an average speed of 610 km/h. IF the trip takes 2.75 h
rusak2 [61]

2.75x610km

1220+7.5x61

1220+427 ... just over

1647

8 0
2 years ago
I need help if you can help me to get 10 points.
Alinara [238K]

Answer:

It allows the reader to feel more connected to her purpose

Explanation:

If Cooper is using personal examples for her argument, she is allowing the reader see more of her point of view, which can also lead them to feel connected to her purpose

6 0
3 years ago
Read 2 more answers
"the velocity of the block is constant, so the net force acting on the block must be zero. Thus the normal force equals the weig
RSB [31]

Answer:

Explanation:

"the velocity of the block is constant, so the net force acting on the block must be zero. Thus the normal force equals the weight and the force of friction equals the applied force" The only thing which is wrongly stated here is that the normal force equals the weight. Normal force is not always equal to weight. If external force is applied at some angle with the horizon , normal force may be more or less than weight. Even in case of an object placed on an  inclined plane , weight is not equal to normal force .

All other parts of the statement are correct.

6 0
3 years ago
An electron is projected with an initial speed Vo = 5.35x10^6 m/s into the uniform field between the parallel plates. The direct
mart [117]

Answer:

 E = 3.04 10⁻⁵ N / C

Explanation:

In this problem we can use the kinematics to find how long it takes the electron to travel the plates

Let's start by reducing the magnitudes to the SI system

              vₓ = 5.35 10⁶ m / s

              x = 2 cm = 2 10⁻² m

              y = 1 cm = 1 10⁻² m

             x = vₓ t

             t = x / vₓ

             t = 2 10⁻² / 5.35 10⁶

             t = 3,738 10⁻⁹ s

This time is also the time it takes for vertical movement to go from the center to the plate, let's look for acceleration with Newton's second law

              F = m a

              a = F / m = e E / m

              y = v_{oy} + ½ a t²

              v_{oy} = 0

We replace

              y = ½ e / m E t²

              E = 2 y m / e t²

Let's calculate

            E = 2  1 10⁻²  9.1 10⁻³¹ / (1.6 10⁻¹⁹  3,738 10⁻⁹)

            E = 18.2 10⁻³³ / 5.98 10⁻²⁸

            E = 3.04 10⁻⁵ N / C

5 0
3 years ago
Charge of uniform density (0.30 nC/m2) is distributed over the xy plane, and charge of uniform density (−0.40 nC/m2) is distribu
soldier1979 [14.2K]

Answer: E = 39.54 N/C

Explanation: Electric field can be determined using surface charge density:

E = \frac{\sigma}{2\epsilon_{0}}

where:

σ is surface charge density

\epsilon_{0} is permitivitty of free space (\epsilon_{0} = 8.85.10^{-12}C^{2}/N.m^{2})

Calculating resulting electric field:

E=E_{1} - E_{2}

E = \frac{\sigma_{1}-\sigma_{2}}{2\epsilon_{0}}

E = \frac{[0.3-(-0.4)].10^{-9}}{2.8.85.10^{-12}}

E=0.03954.10^{3}

E = 39.54

The resulting Electric Field at any point is 39.54N/C.

8 0
3 years ago
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