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3 years ago

Please help i need an explanation

Physics

1 answer:

const2013 [10]3 years ago

6 0

Answer:

Explanation:

All potential and kinetic energy is transferred into heat. Therefore keeping the law of conservation of energy valid. No energy is created nor destroyed only changing shape.

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An object has a mass of 20 grams and a volume of 5 cubic centimeters what is the object density

Solnce55 [7]

20 g / 5 cm^3 = 4 g/cm^3 or 4000 kg / m^3.

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3 years ago

Name five uses of electromagnetic radiation

klio [65]

Answer:

Behaviour and uses of electromagnetic waves

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3 years ago

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How do you get: a = -ω^2*x from: a = -Aω^2*sen(ωt) ?

Firdavs [7]

Answer:

$x = Asin(\omega t)\\v = \frac{dx}{dt} = \omega Acos(\omega t)\\a = \frac{dv}{dt} = -\omega^2Asin(\omega t)= -\omega^2x$

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4 years ago

Matt plays badminton. He serves the birdie with a velocity of 4.25 m/s [right] covering a displacement of 5.2 m [forward]. How m

OLEGan [10]

Answer:

Time taken by birdie’s trip = 1.2235 s (Approx)

Explanation:

Given:

Velocity = 4.25 m/s

Displacement = 5.2 m

Find:

Time taken by birdie’s trip = ?

Computation:

⇒ Time taken = Displacement / Velocity

⇒ Time taken by birdie’s trip = Displacement / Velocity

⇒ Time taken by birdie’s trip = 5.2 m / 4.25 m/s

⇒ Time taken by birdie’s trip = 1.2235 s (Approx)

6 0

3 years ago

A river flows with a uniform velocity vr. A person in a motorboat travels 1.22 km upstream, at which time she passes a log float

storchak [24]

Answer:

t ’= $\frac{1450}{0.6499 + 2 v_r}$ , v_r = 1 m/s t ’= 547.19 s

Explanation:

This is a relative velocity exercise in a dimesion, since the river and the boat are going in the same direction.

By the time the boat goes up the river

v_b - v_r = d / t

By the time the boat goes down the river

v_b + v_r = d '/ t'

let's subtract the equations

2 v_r = d ’/ t’ - d / t

d ’/ t’ = 2v_r + d / t

$t' = \frac{d'}{ \frac{d}{t}+ 2 v_r }$

In the exercise they tell us

d = 1.22 +1.45 = 2.67 km= 2.67 10³ m

d ’= 1.45 km= 1.45 1.³ m

at time t = 69.1 min (60 s / 1min) = 4146 s

the speed of river is v_r

t ’= $\frac{1.45 \ 10^3}{ \frac{ 2670}{4146} \ + 2 \ v_r}$

t ’= $\frac{1450}{0.6499 + 2 v_r}$

In order to complete the calculation, we must assume a river speed

v_r = 1 m / s

let's calculate

t ’= $\frac{ 1450}{ 0.6499 + 2 \ 1}$

t ’= 547.19 s

8 0

3 years ago