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svetoff [14.1K]
3 years ago
10

Charge of uniform density (0.30 nC/m2) is distributed over the xy plane, and charge of uniform density (−0.40 nC/m2) is distribu

ted over the yz plane. What is the magnitude of the resulting electric field at any point not in either of the two charged planes?
Physics
1 answer:
soldier1979 [14.2K]3 years ago
8 0

Answer: E = 39.54 N/C

Explanation: Electric field can be determined using surface charge density:

E = \frac{\sigma}{2\epsilon_{0}}

where:

σ is surface charge density

\epsilon_{0} is permitivitty of free space (\epsilon_{0} = 8.85.10^{-12}C^{2}/N.m^{2})

Calculating resulting electric field:

E=E_{1} - E_{2}

E = \frac{\sigma_{1}-\sigma_{2}}{2\epsilon_{0}}

E = \frac{[0.3-(-0.4)].10^{-9}}{2.8.85.10^{-12}}

E=0.03954.10^{3}

E = 39.54

The resulting Electric Field at any point is 39.54N/C.

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A stream of particles

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3 years ago
A meter stick balances at the 50.0-cm mark. If a mass of 50.0 g is placed at the 90.0-cm mark, the stick balances at the 61.3-cm
Airida [17]

Answer:

126.99115 g

Explanation:

50 g at 90 cm

Stick balances at 61.3 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

mgl_1=Mgl_2\\\Rightarrow M=\dfrac{ml_1}{l_2}\\\Rightarrow M=\dfrac{50\times (61.3-90)}{50-61.3}\\\Rightarrow M=126.99115\ g

The mass of the meter stick is 126.99115 g

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2 years ago
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The moon’s period of revolution is 27 1/3 days, and its period of rotation about its axis is _____.
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It lasts 29 1/2 days.
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Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy
avanturin [10]

Answer:

Explanation:

We know that , If the frictional force on a system is zero , then the total energy of a system will be conserved.

By using energy conservation

KE₁ +  U₁ = KE₂ + U₂

KE₁=Kinetic energy at location 1

U₁ =Potential energy at location 1

KE₂=Kinetic energy at location 2

U₂=Potential energy at location 2

Therefore, Raymond is thinking in a right way.

7 0
3 years ago
A bullet with a mass 2.25g is fired up into the air with a velocity of 187.5 m/s. What is the maximum height of the bullet
Ksivusya [100]

Answer:

1793.7m

Explanation:

From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.

Now the kinetic energy; is

K.E = 1/2 × m × v2

Where m is mass

v is velocity

Hence.

K.E = 1/2 × 2.25 × (187.5)^2

Now this should be same with the potential energy which is given as;

P.E = m× g× h

Where m is mass of object

g is acceleration of free fall due to gravity = 9.8m/S2

h is maximum height substain by the object.

Hence P.E = 2.25 × 9.8 × h

From the foregoing analysis of energy conversation it implies;

1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h

=> 1/2 × (187.5)^2 = 9.8 × h

=>1/2 × (187.5)^2 / 9.8 = h

=> 1793.69m = h

h= 1793.69m

h =1793.7m to 1 decimal place

3 0
3 years ago
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