All categories

3 years ago

The length of a rectangle is 6 centimeters and its area is (6x + 18)square centimeters. Write an expression for the width.

1 answer:

5 0

Area=legnth times width
legnth=6
area=6x+18
subsitute
6x+18=6 times width

undistribute 6 from each term on left side
6(x+3)=6 times width
divide both sides by 6
x+3=width

You might be interested in

What is the surface area of the cube below?

Elden [556K]

Answer:

150 units^2

Step-by-step explanation:

A cube has all equal sides. This one has five units for every side.

There are 6 faces here, and 4 vertices for every face.

The equation would look like this 6 x side^2.

Which would also equal to 6 x 5^2.

If you do this, you will find that the answer is 150 units^2.

7 0

3 years ago

A line has a slope of zero

asambeis [7]

Answer:

Horizontal Line

Step-by-step explanation:

Easy the line has the same Y all throughout it

4 0

3 years ago

Please Help Thank You So Much

VikaD [51]

Answer:

all the possible values of y - x are 4 and 5

all possible values of x/y = 1

6 0

3 years ago

Find the experimental probability Roll dice 1,3,3,4,4 P(1)= I’ll give brainleist

-Dominant- [34]

Answer:

$\mathrm{P(1)\:}=\frac{1}{5}$

Step-by-step explanation:

There are simply 5 possible values in the given set. Out of these, only one of these is the number 1. Therefore, the probability a 1 is drawn (P(1)) is $\fbox{$\frac{1}{5}$}$ .

5 0

3 years ago

Read 2 more answers

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago