Answer:
The motion of ball B will increase
Explanation:
Because if you hit ball A with less force than ball B then that means that ball B will go faster because you had hit ball A will less force witch will not be as faster as ball B.
Answer:
12 moles of MgO
1.8 moles of O₂
5.5 moles of Mg
Explanation:
These questions are all related and they involve comparing the number of moles of reactant to products.
Here we use molar relationship because they express what happens in a reaction much more better.
Problem 1:
2Mg + O₂ → 2MgO
We work from the known to the unknown;
The known is oxygen gas; which is 6moles
Unknown is MgO;
1 mole of O₂ produced 2 mole of MgO
6 moles of O₂ will produce (6 x 2) moles of MgO
= 12 moles of MgO
Problem 2:
2Mg + O₂ → 2MgO
Known; 3.6 moles of Magnesium
Unknown; number of moles of oxygen;
2 moles of Mg reacted with 1 mole of O₂
3.6 moles of Mg will react with
= 1.8 moles of O₂
Problem 3:
2Mg + O₂ → 2MgO
Known: number of of moles of MgO = 5.5moles
Unknown: number of moles of Mg = ?
2 moles of MgO will be produced from 2 moles of Mg
5.5 moles of MgO will be produced from
= 5.5 moles of Mg
Answer:
6.82 g H₂S
General Formulas and Concepts:
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
0.200 mol H₂S
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol
<u>Step 3: Convert</u>
- Set up:

- Multiply:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
6.818 g H₂S ≈ 6.82 g H₂S
Answer:
Explanation:
The relative massive alpha particles could go through the gold foil without being deviated of their trajectory or only small deviations due to the uniformity distribution positive charge of the protons.
<span>ZnS + O --> ZnO + SO
Okay so first you have to count up the number of elements on each side of the equation. Your objective is to have the same number of each element on both sides.
Left Side:
Zn - 1
S - 1
O - 1
Right Side:
Zn - 1
S - 1
O - 2
Since there are two oxygens on the right side, you have to add a coefficient of 2 to the oxygen on the left side. The coefficient tells us that that element or molecule is being multiplied by the value of coefficient. Since we're adding a coefficient of 2 to the oxygen on the left side, there are now 2 oxygens on that side. Because that is the same amount of oxygen as on the right, the equation is now balanced.
Your final equation should look like this: </span>ZnS + 2O --> ZnO + SO
In conclusion, the answer is 2.