What are the missing coefficients? _Fe + _Cl2 → _FeCl3
2 answers:
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Answer:
12 moles of MgO
1.8 moles of O₂
5.5 moles of Mg
Explanation:
These questions are all related and they involve comparing the number of moles of reactant to products.
Here we use molar relationship because they express what happens in a reaction much more better.
Problem 1:
2Mg + O₂ → 2MgO
We work from the known to the unknown;
The known is oxygen gas; which is 6moles
Unknown is MgO;
1 mole of O₂ produced 2 mole of MgO
6 moles of O₂ will produce (6 x 2) moles of MgO
= 12 moles of MgO
Problem 2:
2Mg + O₂ → 2MgO
Known; 3.6 moles of Magnesium
Unknown; number of moles of oxygen;
2 moles of Mg reacted with 1 mole of O₂
3.6 moles of Mg will react with = 1.8 moles of O₂
Problem 3:
2Mg + O₂ → 2MgO
Known: number of of moles of MgO = 5.5moles
Unknown: number of moles of Mg = ?
2 moles of MgO will be produced from 2 moles of Mg
5.5 moles of MgO will be produced from = 5.5 moles of Mg
Answer:
6.82 g H₂S
General Formulas and Concepts:
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
0.200 mol H₂S
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
6.818 g H₂S ≈ 6.82 g H₂S