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AnnZ [28]
3 years ago
8

A small cork is charged to +4.50 mC. Find the number of excess elementary charges (protons or electrons)

Physics
1 answer:
Irina-Kira [14]3 years ago
7 0

Answer:

The third choice: 2.81*10^{16} \: \text{protons}

Explanation:

The cork is positively charged, therefore we know tat there must be excess of positively charged protons present.

The charge p^+ of a proton is

p^+ = +1.6*10^{-19}C;

therefore, the number n that makes up a charge of +4.5mC is

n = \dfrac{+4.5mC}{+1.6*10^{-19}C}  = \dfrac{+4.5*10^{-3}C}{+1.6*10^{-19}C}

\boxed{n =2.81*10^{16} \: \text{protons}}

which is the 3rd choice.

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vesna_86 [32]
Chemicals are brought in through photosynthesis

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3 years ago
An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
e=-1.6 \cdot 10^{19}C
Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C
7 0
3 years ago
Una cámara fotográfica analógica (no digital) tiene dos lentes intercambiables. Uno de foco 55mm y el otro de 200 mm. Toma una f
Sergeu [11.5K]

Answer:

f = 55mm,     h ’= -9.89 cm

f = 200 mm,  h ’= 42.5 cm

Explanation:

For this exercise let's start by finding the distance to the image, using the equation of the constructor

         \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distances to the object and image, respectively

lens with f₁ = 55mm = 0.55cm

         \frac{1}{q} = \frac{1}{f} - \frac{1}{p}

         \frac{1}{q_1} = \frac{1}{0.55} - \frac{1}{10}

          \frac{1}{q_1} = 1.718

          q₁ = 0.582 m

lens with f₂ = 200mm = 2m

           \frac{1}{q_2} =   \frac{1}{2} - \frac{1}{10}

            \frac{1}{q_2} = 0.4

            q₂ = 2.5 m

the magnification of a lens is given by

            m = \frac{h'}{h} = -  \frac{q}{p}

             h ’= - \frac{q}{p} \ h

let's calculate for each lens

f = 55mm

             h '= - 0.582 / 10 1.7

             h ’= 0.0989 m

             h ’= -9.89 cm

f = 200 mm

             h '= - 2.5 / 10 1.7

             h ’= -0.425 m

             h ’= 42.5 cm

The negative sign indicates that the image is real and inverted

4 0
3 years ago
Beryllium, Be, and chlorine, Cl, form a binary ionic compound with a one-to-two ratio of beryllium ions to chloride ions. The fo
Tanya [424]
The correct answer among the choices above is option C. <span>Beryllium, Be, and chlorine, Cl, form a binary ionic compound with a one-to-two ratio of beryllium ions to chloride ions.</span> The chemical formula for the compound of beryllium and chlorine is BeCl2. 
5 0
3 years ago
Read 2 more answers
18. The displacement of an object moving 330 km North for 2 hours and an additional 220
motikmotik

Answer:

Explanation:

1) Displacement of the object will be gotten using simply adding the distances since they are goinf in the same direction (positive y direction)

Displacement= 330km + 220km

Displacement = 550km North

2) For a falling body, the body will possess positive acceleration due to gravity because it is falling under the influence of gravitational force. If a body is not under the influence of gravity and is thrown up, such body wont come back down. Hence the value of acceleration due to gravity of a body falling to the ground is +9.8 m/s² (note that the unit of acceleration is m/s²)

3 0
4 years ago
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