Answer:
(a) The equivalent spring constant is 598.485 N/m
(b) The work done is 46.926 J
Explanation:
From Hooke's law of elasticity
K (spring constant) = F/e
F is the range of force exerted = 237 - 0 = 237 N
e is the extension of bowstring = 0.396 m
K = F/e = 237/0.396 = 598.485 N/m
Work done = 1/2 Fe = 1/2 × 237 × 0.396 = 46.926 J
Answer:
The time taken for the train to cross the bridge is 9.01 s
Explanation:
Given;
length of the train, L₁ = 90 m
length of the bridge, L₂ = 0.06 m
speed of the train, v = 10 m/s
Total distance to be traveled, = L₁ + L₂
= 90 m + 0.06 m
= 90.06 m
Time of motion = Distance / speed
Time of motion = 90.06 / 10
Time of motion = 9.006 s ≅ 9.01 s
Therefore, the time taken for the train to cross the bridge is 9.01 s
Answer:
34000 J or 34 kJ
Explanation:
From the question, The energy needed to just melt the ice cube does not requires any external temperature or change in temperature, Hence it is called latent heat
By Applying,
Q' = C'm........................ Equation 1
Where Q' = Latent heat, C' = Specific latent heat of fusion of water, m = mass of ice.
Given: C' = 340000 J/kg, m = 100 g = 0.1 kg
Substitute into equation 1
Q' = 0.1(340000)
Q' = 34000 J
Q' = 34 kJ
Si familia no estoy bien por que la chila en la espanol gracias
Answer:
Explanation:
If v be the velocity just after the rebound
Kinetic energy will be converted into potential energy
1/2 m v² = mgh
v² = 2gh
v = √ 2gh
= √ 2 x 9.8 x .96
= 4.33 m / s