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2 years ago

A small cork is charged to +4.50 mC. Find the number of excess elementary charges (protons or electrons)

Physics

1 answer:

Irina-Kira [14]2 years ago

7 0

Answer:

The third choice: $2.81*10^{16} \: \text{protons}$

Explanation:

The cork is positively charged, therefore we know tat there must be excess of positively charged protons present.

The charge $p^+$ of a proton is

$p^+ = +1.6*10^{-19}C$ ;

therefore, the number $n$ that makes up a charge of $+4.5mC$ is

$n = \dfrac{+4.5mC}{+1.6*10^{-19}C} = \dfrac{+4.5*10^{-3}C}{+1.6*10^{-19}C}$

$\boxed{n =2.81*10^{16} \: \text{protons}}$

which is the 3rd choice.

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$F_{23}=8.99x10^{9}N\frac{m^{2} }{C^{2} }\frac{(46x10^{-6}C)(52x10^{-6}C) }{(0.17m)^{2} }$

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$F_{net}=$ ∑F

$F_{net}=F_{12}+F_{23}$

$F_{net}=-1148.48N+744.09N$

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