Answer:
Car H
Explanation:
Frictional force is a resistant force. It is given as:
F = u*m*g
Where u = coefficient of friction
m = mass
g = acceleration due to gravity
From the formula above, we see that frictional force is dependent on the mass of object and the coefficient of friction.
Since they all have the same tires, the coefficient of friction between the tire and the floor is the same for each car. Acceleration due to gravity, g, is constant.
The only factor that determines the frictional force of each car is the mass. Hence, the more the mass, the more the frictional force.
So, the most massive car will have the most frictional force and hence, will come to a stop quicker than the others. The least massive car will have the least frictional force and so, will take a longer time to stop.
Answer:
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Explanation:
Answer:
R = 8.01 m
Explanation:
We can solve this problem using the projectile launch equations. The jump length is the throw range
R = v₀² sin 2θ / g
in the exercise they give us the initial speed of 9.14 m / s and in the launch angle 35º
let's calculate
R = 9.14² sin (2 35) / 9.8
R = 8.01 m
this is the jump length
