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lisabon 2012 [21]
4 years ago
5

Consider the following distinct forces:______________________________.

Physics
1 answer:
Kamila [148]4 years ago
5 0

Answer:

1 and 2

Explanation:

It is given that, force exerted by air is negligible in any way.

Also, it is given that channel is in the shape of a segment of a circle with its center at O.

When it is within the frictionless channel at position 'Q',

A gravity exerts force on the ball in the downward direction. On the other hand, the channel pointing from Q to O also exerts a force on the ball.

However, there is no any force in the direction of motion. On the other hand, he channel pointing from O to Q does not exert a force on the ball.

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2: Fusion occurs constantly on our sun.When nuclei fuse create a heavier nuclear and produce a little leftover energy in the process
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A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block move
NeTakaya

Magnitude of acceleration

Explanation:

We know that acceleration can increase depending in the force applied on an object, any object with a greater mass will apply a greater force. F = M(a).

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Christine Ladd-Franklin was a mathematician and psychologist who faced many obstacles as a woman, but she persevered and made si
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3 years ago
A ball is launched horizontally at 150 m/s from a cliff. What is its vertical speed after 3 seconds?
Setler79 [48]

Answer:

v_f = 30 m/s

Explanation:

v_f = v_I + a*t

v_f = 0m/s + (9.81m/s²)*(3s)

v_f = 29.43m/s

v_f = 30 m/s

Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.

3 0
3 years ago
A box rests on a horizontal, frictionless surface. a girl pushes on the box with a force of 17 n to the right and a boy pushes o
Komok [63]
Refer to the diagram shown below.

The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.

By definition,
Work = Force x Distance.

(a) The work done by the girl is
     W₁ = (17 N)*(3.5 m) = 59.5 J

(b) The work done by the boy is
     W₂ = (13 N)*(-3.5 m) = - 45.5 J

(c) The work done by the net force  is
    W₃ = (4 N)*(3.5 m) = 14 J

Note that W₃ = W₁ + W₂

Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J

5 0
4 years ago
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