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Nastasia [14]
3 years ago
11

A student places a block on a table and hangs one mass from the block. The student lets the block go and observes the block move

towards the end of the table where the mass was located. The student then places the block on the table and hangs a second, larger mass from the opposite end of the block. The block moves in the opposite direction as the first trial. What does this experiment demonstrate? Use information from the experiment to support your answer.​
Physics
1 answer:
NeTakaya3 years ago
7 0

Magnitude of acceleration

Explanation:

We know that acceleration can increase depending in the force applied on an object, any object with a greater mass will apply a greater force. F = M(a).

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A comet with a mass of 7.85 × 1011 kg is moving with a velocity of 25,000 m/s. calculate its kinetic energy.
Nadusha1986 [10]
The kinetic energy of an object is given by:
K= \frac{1}{2}mv^2
where
K is the kinetic energy
m is the mass of the object
v is its velocity.

The comet in our problem has a mass of m=7.85 \cdot 10^{11} kg and a velocity of v=25000 m/s, so its kinetic energy is:
K= \frac{1}{2}(7.85 \cdot 10^{11} kg)(25000 m/s)^2=2.45 \cdot 10^{20}J
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How the properties of sound waves change as they spread out in a spherical pattern
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A car goes from 0 to 100 km/hr in 10 seconds. What is its acceleration
makvit [3.9K]

Answer:

a= 2.7 m/s^2

Explanation:

acceleration: a

speed: V

Vf = final speed

Vi= initial speed (initial = beginning)

100 km/hour --> m/s

divide the speed value by 3.6

100/3.6= 27.8 m/s

a = \frac{final speed - initialspeed}{time}

a= \frac{Vf - Vi}{t} \\

a= \frac{27-0}{10}

a= \frac{27}{10}

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5 0
4 years ago
2. A Plate 0.02 mm distance from a fixed Plate moves at a velocity Of 0.6mls and requires a force of 1.962 N Per unit area to ma
Marizza181 [45]

Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So,  μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

5 0
3 years ago
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