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worty [1.4K]
3 years ago
14

List all the factor pairs for 48 make a tabletop to help

Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0
1  and 48 are a factor pair of 48 since 1 x 48= 48

2 and 24 are a factor pair of 48 since 2 x 24= 48

3 and 16 are a factor pair of 48 since 3 x 16= 48

4 and 12 are a factor pair of 48 since 4 x 12= 48

6 and 8 are a factor pair of 48 since 6 x 8= 48

8 and 6 are a factor pair of 48 since 8 x 6= 48

12 and 4 are a factor pair of 48 since 12 x 4= 48

16 and 3 are a factor pair of 48 since 16 x 3= 48

24 and 2 are a factor pair of 48 since 24 x 2= 48

48 and 1 are a factor pair of 48 since 48 x 1= 48

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Linda West, a dental lab technician, pays three times as much
Natalka [10]

9514 1404 393

Answer:

  • vision: $13.50
  • dental: $40.50
  • health: $162.00

Step-by-step explanation:

Let d, v, h represent the costs of dental, vision, and health insurance, respectively. The cost relations are ...

  d = 3v . . . . . . . . . . . . . . . dental is 3 times vision

  h = 3(v +d) . . . . . . . . . . . health is 3 times vision and dental combined

  d + v + h = 9360 . . . . . annual premium

Substituting for h, we have ...

  d + v + (3(d +v)) = 9360

Substituting for d, we have ...

  3v +v +3(3v +v) = 9360

  16v = 9360

  v = 585

  d = 3v = 1755

  h = 3(d+v) = 7020

These are the total annual premiums. Linda pays 1/26 of 60% of this every two weeks. That fraction is 0.60/26 = 3/130.

a) Linda's biweekly vision insurance deduction is (585)(3/130) = $13.50

b) Linda's biweekly dental insurance deduction is (1755)(3/130) = $40.50

c) Linda's biweekly health insurance deduction is (7020)(3/130) = $162.00

_____

<em>Additional comment</em>

We know dental is 3v and health is 3(3v+v) = 12v = 4d. That is, once we find Linda's share of the biweekly vision premium, we can find the others by multiplying it by a suitable factor.

6 0
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Solve 2 (x – 3) &gt; -3(-3+x)
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Answer:

x>3

Step-by-step explanation:

2 ( x-3) > -3(-3+x)\\ 2x-6) > 9-3x\\5x>15\\x>3

6 0
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Answer:

24

Step-by-step explanation:

2;3;4;x

2x 3x =6x

six is equal to the x an. four

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4 years ago
Five cards are dealt form 52. a) How many different hands can be dealt? b) How many hands will contain 4 hearts? c) How many han
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The answer will be d. hope that helped
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Help :(! <br> Please .<br> :(
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