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Dmitry [639]
4 years ago
12

Complete to find the product. 64 X 43

Mathematics
1 answer:
nataly862011 [7]4 years ago
8 0

64 x 43 = 2,752 hope it helps!

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A spherical shell whose inner radius is 2 cm and whose outer radius is 8 cm is made of material of varying density. At a point {
Flauer [41]

Answer:

Density is 16.11 units, If it is less than the density of water in the same units, the sphere will float.

Step-by-step explanation:

We have to:

Mass of shell at distance r from:

Density = mass / volume, if we solve for mass we have:

Mass = volume * density

replacing:

Mass = (4 * pi * (r ^ 2) * dr) * (0.39r ^ 2)

Mass = 1.68 * pi * r ^ 4 * dr

Mass = 1.68 * pi integral from 2 to 8 of {r ^ 4 * dr}

Mass = 1.68 * 3.14 * (r ^ 5) / 5 when r equals 2 to 8, replacing:

Mass = 1.68 * 3.14 * [(8 ^ 5/5 - (2) ^ 5/5]

Mass = 34537.79

Now the volume would be: (4/3) * pi * r ^ 3, we replace:

(4/3) * 3.14 * 8 ^ 3 = 2143.57

Density = 34537.79 / 2143.57 = 16.11 units

If it is less than the density of water in the same units, the sphere will float.

6 0
3 years ago
sheila works for a fishing companyshe is paid $20 per day and an additional $2 fo ea lobster she catches. she wats to know how m
kari74 [83]
5 days x $20 payment each day=$100
Goal Profits=$130
$130-$100=$30
$30/$2 per lobster= 15 lobsters
5 0
3 years ago
Someone plz help:)))))
trapecia [35]
Help is when you are needed of someone to help you
8 0
4 years ago
The value of a new car decreases by about 15% in the first year. How much will a car be worth after one year if its initial valu
Masja [62]

Answer:

(a)

$850.

(b)

$4250.

(c)

$4267.

Step-by-step explanation:

It is given that the value of a new car decreases by about 15% in the first year.

(a)

Now we are asked to find the cost of a car after one year; if we are given the initial value of car=$1000.

As the rate decreases by 15%.

that means we have to pay (100-15)% of the initial amount.

i.e. we have to pay 85% of the initial amount.

Hence the amount one has to pay= 85% of 1000.

which is equal to =85%×1000

⇒   =\dfrac{85}{100}\times 1000\\\\=85\times 10\\\\=850

Hence, the amount of car after one year when initaial amount is $1000 is:

$850.

(b)

if initial amount=$ 5000

then amount one has to pay after one year:

85\%\times 5000\\ \\=\dfrac{85}{100}\times 5000\\\\=4250

Hence, the amount of car after one year when initaial amount is $5000 is:

$4250.

(c)

if initial amount=$ 5020

then amount one has to pay after one year:

85\%\times 5020\\ \\=\dfrac{85}{100}\times 5020\\\\=4267

Hence, the amount of car after one year when initaial amount is $5020 is:

$4267.

7 0
3 years ago
Rename the number 82000
Mrrafil [7]
<span>a few ways to rename 82 thousands is 82,000 or eighty-two thousands.</span>
6 0
3 years ago
Read 2 more answers
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