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sertanlavr [38]
3 years ago
9

When x = -3 on the graph of y = 2|x| + 3 what will be the y-coordinate?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0
Substitute -3 into the equation

y = 2|x| + 3
y = 2 (3) + 3
y = 6 + 3
y = 9

Answer D
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Will give brainliest!! Using the measurements of the shapes.. determine the area and perimeter of the irregular polygon.
yan [13]

Answer:

p=28.2\:\text{units},\\A=40.2\:\text{square units}}

Step-by-step explanation:

The irregular shape's area consists of the sum of the areas of all the shapes that make it up.

Area of pink triangle: \frac{1}{2}\cdot 3 \cdot 3=4.5

Area of purple square: 3^2=9

Area of green quadrilateral: 3\cdot 2.9=8.7

Area of blue triangle: \sqrt{10.25(10.25-8.5)(10.25-6)(10.25-6)}=17.99989

Therefore, the area of the irregular polygon is 4.5+9+8.7+17.99989\approx \boxed{40.2\:\text{square units}}.

The perimeter of the irregular polygon consists of certain shred sides from the four polygons that make up:

p=3+3+3+4.2+3+6+6=\boxed{28.2\:\text{units}}

5 0
2 years ago
Josephine can correct her students test papers in 5 hours, but if her teacher’s assistant helps, it would take them 3 hours. How
ipn [44]

<u><em>7 hours 30 minutes</em></u>

<u><em></em></u>

Sure hope this helps you :D

4 0
2 years ago
If you answer this pls answer the other questions i asked for brainly
vlada-n [284]

Answer:

2 is the answer

Step-by-step2 explanation:

3 0
3 years ago
Read 2 more answers
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.â  Suppose a small group of 11 Allen's humming
alexira [117]

Answer:

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=3.15 represent the sample mean

\mu population mean (variable of interest)

\sigma=0.38 represent the population standard deviation

n=11 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that z_{\alpha/2}=1.28

Now we have everything in order to replace into formula (1):

3.15-1.28\frac{0.38}{\sqrt{11}}=3.003    

3.15+ 1.28\frac{0.38}{\sqrt{11}}=3.297    

So on this case the 80% confidence interval would be given by (3.003;3.297)

And the margin of error is given by:

ME = 1.28\frac{0.38}{\sqrt{11}}= 0.147    

8 0
3 years ago
Could some please help me with these two
damaskus [11]

Answer:

+3

Step-by-step explanation:

(-m)^(-3) = -m^3, since (-1)^-3 = 1 / (-1).

If m = 2 then we have -2^(-3), or  -1 / [2^3]), or -1/8.

Finally, if n = -24, the original expression becomes

(-1/8)(-24) = +3

Second problem:  Only the first expression simplifies to a negative result.  

4 0
3 years ago
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