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liubo4ka [24]
4 years ago
5

The acceleration of a particle is given by a = -kt^2, where a is in meters per second squared and the time t is in seconds. If t

he initial velocity of the particle at t=0 is__________.
Physics
1 answer:
QveST [7]4 years ago
4 0

Answer:

Velocity is zero.

Explanation:

Given:

  • acceleration of particle, a=-k.t^2\ m.s^{-2}
  • time of observation, t=0\ s

We know that acceleration is defined as the rate of change in velocity and hence we integrate the expression of acceleration.

<u>Now the velocity can be given as:</u>

v=\int\limits {a} .\, dt=-k.\frac{t^3}{3}

Put t = 0 we get:

v=0\ m.s^{-1}

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Answer:

Explanation:

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A particle released during the fission of uranium-235 is a(n) ________
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3 years ago
If 500g of water at 20 degrees C is mixed with 750g of water at 30 degrees C, what will the temperature of the mixture be?
hjlf

Answer:

26 ^\circ C

Explanation:

Given that the temperature of  500g of water and 750 g of water are

at 20^{\circ}C and 30^\circ C respectively.

Let m_1=500g, T_1= 20^\circ C

and m_2=750g, T_2= 30^\circC.

The specific heat capacity of water is,

C= 4.186 J/g ^\circ C.

Let the final temperature of the mixture be T^\circ C.

As there is no energy loss, so, the energy loss by the water at higher temperature, i.e. 30^\circ C, will be equal to the energy gain by the water at lower temperature, i.e. 20^{\circ}C.

m_2C (T_2-T)=m_1C(T-T_1)

\Rightarrow m_2 (T_2-T)=m_1(T-T_1) [ both sides divided by C ]

\Rightarrow m_2T_2-m_2T=m_1T-m_1T_1

\Rightarrow m_1T+m_2T=m_1T_1+m_2T_2

\Rightarrow T=\frac{m_1T_1+m_2T_2}{m_1+m_2}

Now, putting the given value in the above equation, we have

\Rightarrow T=\frac {500\times 20+750\times 30}{500+750}

\Rightarrow T=26^\circ C.

Hence, the temperature of the mixture will be 26 ^\circ C.

5 0
3 years ago
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2. The vibration is parallel to the direction of travel of longitudinal waves.

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4.  You produce a transverse wave when you move one end of a
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5.  All waves have wavelengths.


3 0
3 years ago
Read 2 more answers
Please solve this problem!​
siniylev [52]

Answer:

Send a clear photo again

Explanation:

And tag me

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