A force of 40N is applied to a 28 g mass, what is the acceleration? (round to the hundredths place)
1 answer:
Answer:
1428.6m/s²
Explanation:
Given parameters:
Force applied on the body = 40N
Mass of the body = 28g
1000g = 1kg
28g will therefore be 0.028kg
Unknown:
Acceleration = ?
Solution:
To solve this problem, we use the expression derived from Newton's second law of motion.
Force = mass x acceleration
Insert the parameters and solve;
40 = 0.028 x acceleration
Acceleration = = 1428.6m/s²
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<h2>Answer:</h2>
1.77V
<h2>Explanation:</h2>The electromotive force voltage (E) in a cell, is related to the lost voltage () and the terminal voltage (
) as follows;
E = -
Where;
The lost voltage () is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e
= I x r
<em>Substitute </em><em> = I x r into equation (i) as follows;</em>
E = - (I x r) ----------------------(ii)
<em>According to the question;</em>
E = 1.54V
I = 2.15A
r = 0.105Ω
<em>Substitute these values into equation(ii) as follows;</em>
1.54 = - (2.15 x 0.105)
1.54 = - (0.22575)
1.54 = - 0.22575
<em>Solve for </em><em>;</em>
= 1.54 + 0.22575
= 1.54 + 0.22575
= 1.77V
Therefore, the terminal voltage of the cell is 1.77V