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puteri [66]
3 years ago
11

A force of 40N is applied to a 28 g mass, what is the acceleration? (round to the hundredths place)

Physics
1 answer:
Leno4ka [110]3 years ago
7 0

Answer:

1428.6m/s²

Explanation:

Given parameters:

Force applied on the body  = 40N

Mass of the body  = 28g

                    1000g  = 1kg

                      28g will therefore be 0.028kg

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use the expression derived from Newton's second law of motion.

         Force  = mass x acceleration

Insert the parameters and solve;

            40  = 0.028 x acceleration

           Acceleration  = \frac{40}{0.028}   = 1428.6m/s²

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Simora [160]

Answer:

F = 53153.36[N]

Explanation:

In order to solve this problem, we must first use the principle of conservation of energy which is transformed from potential energy to kinetic, in this way we can determine the velocity at which the person enters the water.

E_{pot}=E_{kin}\\m*g*h=\frac{1}{2}*m*v^{2}

where:

m = mass = 100 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 9 [m]

v = velocity [m/s]

Now replacing we can determinate the velocity.

v^{2}=2*g*h\\v=\sqrt{2*g*h}\\v=\sqrt{2*9.81*9}\\v = 13.28[m/s]

Then we can calculate the momentum which can be calculated as the product of force by time, this momentum is also equal to the product of mass by velocity.

P=m*v\\and\\P =F*t\\F*t=m*v

Now replacing:

F = impact force [N]

t = time = 0.025 [s]

m = 100 [kg]

v = velocity = 13.28 [m/s]

F*0.025=100*13.28\\F=53153.36[N]

8 0
3 years ago
The direction of electrical force is based on the fact that like charges will
tigry1 [53]

yes

Explanation:

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Compare the weight of a mountain climber when she is at the bottom of a mountain with her weight when she is at the top of the m
kakasveta [241]

Answer:

The correct answer is  a. Both are the same

Explanation:

For this calculation we must use the gravitational attraction equation

    F = G m M / r²

Where M will use the mass of the Earth, m the mass of the girl and r is the distance of the girl to the center of the earth that we consider spherical

To better visualize things, let's repair the equation a little

     F = m (G M / r²)

The amount in parentheses called acceleration of gravity, entered the force called peos

     g = G M / r²

     F = W

    W = m g

When analyzing this equation we see that the variation in the weight of the girl depends on the distance, which is the radius of the earth plus the height where the girl is

    r = Re + h

    Re = 6.37 10⁶ m

    r² = (Re + h)²

    r² = Re² (1 + h / Re)²

Let's replace

    W = m (GM / Re²)   (1+ h / Re)⁻²

    W = m g   (1+ h / Re)⁻²

This is the exact expression for weight change with height, but let's look at its values ​​for some reasonable heights h = 6300 m (very high mountain)

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Therefore, the negligible weight reduction, therefore, for practical purposes the weight does not change with the height of the mountain on Earth

The correct answer is a

4 0
3 years ago
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Scilla [17]

Answer:

Explained.

Explanation:

Let me explain the two cases in by one.

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(2) When Jacket is Hanging in a closet, its temperature would be roughly close to room temperature and when we would place a thermometer it would not indicate any change on its scale.

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Bumek [7]

Answer:

the first one

Explanation:

3 0
3 years ago
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