Question

Write the electron configuration for the following elements. (1) Neon, (2) Zinc, (3) Tungsten, (4) Magnesium

Answer 1

Explanation:

Hey there!!

We generally use s,p,d,f formula.

So, let's do with it.

1.Neon

Atomic no. = 10

So, Its electronic configuration is;

$= 1 {s}^{2} .2 {s}^{2} 2 {p}^{6}$

2.Zinc.

Atomic no. = 30

So, it's electronic configuration is;

$= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}$

3. Tungsten.

Atomic no. = 74.

So, it's electronic configuration is;

$= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6} 6 {s}^{2} 4 {f}^{14} 5 {d}^{4}$

4. Magnesium.

Atomic no. = 12

So, the electronic configuration is ;

$= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6}3 {s}^{2}$

Hope it helps...