Answer:
the same is what is this question like what did u exame
Answer:
0.774g of ethanol
0.970mL of ethanol
Explanation:
Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.
In the problem, you need to prepare a 1.2m solution of ethanol (Solute) in t-butanol (solvent).
14.0g of butanol are <em>0.014kg </em>and as you want to prepare the 1.2m solution, you need to add:
0.014kg × (1.2moles / kg) = 0.0168 moles of solute = Moles of ethanol
To convert moles of ethanol to mass you require molar mass (Molar mass ethanol, C₂H₅OH = 46.07g/mol). Thus, mass of 0.0168 moles are:
0.0168moles Ethanol ₓ (46.07g / mol) =
<h3>0.774g of ethanol</h3>
And to convert mass in g to mL you require density of the substance (Density of ethanol = 0.798g/mL):
0.774g ₓ (1mL / 0.798g) =
<h3>0.970mL of ehtanol</h3>
Answer:
ΔG° = 1747.523
Explanation:
The parameters mentioned are;
Gibbs Free energy ΔG°
Equilibrium constant Kc
Temperature T = 37 + 273 = 310 (upon conversion to kelvin temperature)
The formular relating all three parameters is given as;
ΔG° = -RTlnKc
Where; R = rate constant = 8.314 J⋅K−1⋅mol−1
Upon solving;
ΔG° = - 8.314 * 310 * ln(1.97)
ΔG° = 1747.523
Answer:
4 mL
Explanation:
Use the density formula, d = m/v
Plug in the density and mass to solve for v:
4 = 16/v
4v = 16
v = 4
So, the volume is 4 mL
Answer:
o k
Explanation:
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