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ANEK [815]
4 years ago
10

How do i Round the value 44.981 g to three significant figures.

Chemistry
1 answer:
allochka39001 [22]4 years ago
5 0
45.0g
I hope that this helps
You might be interested in
Complete the mechanism for the acid-catalyzed hydrolysis of the epoxide in alcohol by adding any missing atoms, bonds, charges,
Sauron [17]

Answer:

See explanation below

Explanation:

You are missing the structure, therefore, I will do an example with one that I found on another place to try to explain.

This acid mechanism always involves carbocations, and positive charges, never negative because we are in acidic mediums.

In the first step, the lone pairs of the oxigen from the epoxide, substract one hydrogen of the reactant.

Second step, the lone pairs of the oxygen from the reactant, do a nucleophylic attack to the carbon of the epoxide. In this case, it will do it to the most substitued carbon.

Then, in the third step by acid base equilibrium, the hydrogen from the reactant that attacked, is substracted from the molecule by a molecule of water (We are in acid medium, therefore, there is traces of water) and the final structure is formed.

Check picture for mechanism:

4 0
3 years ago
Which is the correct empirical formula for C6H1206?
Bas_tet [7]

Explanation:

the correct empirical formula for C6H12O6 is CH2O...

hope it will help....

8 0
3 years ago
What temperature in kelvin does 60.5 liters of sulfur dioxide occupy if there are 2.5 mol at 0.75 atm??
7nadin3 [17]
 The temperature  in kelvin  does  60.5  liters of sulfur  dioxide  occupy  if there  are  2.5  mole  at 0.75 atm  is   221.07  kelvin 

              Explanation
      This is  calculated using   ideal  gas  equation, that is  PV=nRT
where,  P(pressure)  = 0.75 atm
             V(volume)  = 60.5 L
             n(moles)  = 2.5 mole
             R( gas  constant) = 0.0821 L.atm/mol.k
            T(temperature  =?

by  making   T  the subject   of  the formula  
T  is  therefore =Pv/nR

T= (0.75 atm  x  60.5 L) / (  2.5 molex 0.0821  L.atm/mol.K)  = 221.07 kelvins

6 0
3 years ago
The following boiling points correspond to the substances listed. Match the boiling points to the substances by considering the
Julli [10]

Answer:

CH₄                                - 162 ⁸C

CH₃CH₃                          -88.5 ⁸C

(CH₃)₂ CHCH₂CH₃         28 ⁸C

CH₃3(CH2)₃CH₃             36 ⁸C

CH₃OH                           64.5 ⁸C

CH₃CH₂OH                     78.3 ⁸C

CH₃CHOHCH₃                82.5 ⁸C

C₅H₉OH                         140 ⁸C

C₆H₅CH₂OH                   205 ⁸C

HOCH₂CHOHCH₂OH    290 ⁸C

Explanation:

To answer this question we need first to understand that for organic compounds:

a. Non polar compounds have lower boiling points than polar ones of similar structure and molecular weight.

b. Boiling points increase with molecular weight.  In alkane compounds if we compare  isomers, the  straight chain isomer will have a higher boiling point than the branched one (s) because of London dispersion intermolecular forces.

a. The introduction of hydroxyl groups increase the intermolecular forces and hence the boiling points because the electronegative oxygen, and, more importantly the presence  of hydrogen bonds.

Considering the observations above, we can match the boiling points as follows:

CH₄                                - 162 ⁸C

CH₃CH₃                          -88.5 ⁸C

(CH₃)₂ CHCH₂CH₃         28 ⁸C

CH₃3(CH2)₃CH₃             36 ⁸C

CH₃OH                           64.5 ⁸C

CH₃CH₂OH                     78.3 ⁸C

CH₃CHOHCH₃                82.5 ⁸C

C₅H₉OH                         140 ⁸C

C₆H₅CH₂OH                   205 ⁸C

HOCH₂CHOHCH₂OH    290 ⁸C

Note: There was a mistake in the symbols used for the  162 and 88.5 values which are negative and correspond to the common gases methane and ethane

7 0
3 years ago
In the reaction between Lithium Sulfate and an excess of Lead (II) Nitrate, how many molecules of Lithium Nitrate can be expecte
siniylev [52]

Answer:

1.46x10^{23}molecules \ LiNO_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Li_2SO_4 + Pb(NO_3)_2 \rightarrow PbSO_4+2LiNO_3

Thus, since lead (II) nitrate is in excess, we can directly compute the moles of lithium nitrate by applying the 1:2 molar ratio between them in the chemical reaction as well as the molar mass of Lithium Sulfate that is 110 g/mol for the stoichiometric shown below factor:

n_{LiNO_3}=13.3gLi_2SO_4*\frac{1molLi_2SO_4}{110gLi_2SO_4} *\frac{2molLiNO_3}{1molLi_2SO_4} =0.242molLiNO_3

Finally, by using the Avogadro's number we are able to compute the molecules:

0.242molLiNO_3*\frac{6.022x10^{23}molecules\ LiNO_3}{1mol}=1.46x10^{23}molecules \ LiNO_3

Best regards.

5 0
4 years ago
Read 2 more answers
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