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FrozenT [24]
3 years ago
6

Which statements best describe the atoms of the gas neon? Check all that apply.

Physics
2 answers:
Anni [7]3 years ago
5 0
What are the statements?

RUDIKE [14]3 years ago
4 0

Answer;

They move at high speeds.

They move freely in all directions.

They move constantly.

They are far apart.

Explanation;

-Neon is a chemical element with symbol Ne and atomic number 10, which means an atom of neon has 10 electrons and 10 proton. It is a noble gas.

-Neon is a colorless, odorless, inert monatomic gas under standard conditions.

- Neon is a light, very inert gas as it does not form compounds with other substances and is odorless.  Neon glows when a high electrical voltage is passed through it.

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Answer:

the mark of the broken end is 2.6 cm so, we use the scale from the next full mark i.e. 3cm

Explanation:

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Two polarizing sheets have their transmission axes crossed so that no light is transmitted. A third sheet is inserted so that it
jek_recluse [69]

Answer:

a)    I= I₀ (cos²θ - cos⁴θ)    b) 75.5º

Explanation:

a) For this exercise we must use Malus's law

         I = I₀ cos² θ

where tea is the angle between the two polarizers.

We apply this expression to our case

* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical

         I₁ = I₀ cos² θ

* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.

The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical

              θ₂ = 90- θ’ = θ

fiate that in the exercise we must take a reference system and measure everything with respect to this system.

          I = I₁ cos² θ'

       

we substitute

         I = (I₀ cos² tea) cos² (θ - 90)

        cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ

         I = Io cos² θ sin² θ

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       sin²θ = 1 - cos²θ

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b) to find when the intensity is maximum,

we can use that we have an extreme point when the drift is zero

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whereby

            cos θ - 2 cos³ θ = 0

            cos θ ( 1 - 2 cos² θ) = 0  

The zeros of this function are in

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Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.

Consequently, the angle that allows the maximum intensity to pass is 75.5º

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