All categories

3 years ago

Which statements best describe the atoms of the gas neon? Check all that apply.

Physics

2 answers:

Anni [7]3 years ago

5 0

What are the statements?

RUDIKE [14]3 years ago

4 0

Answer;

They move at high speeds.

They move freely in all directions.

They move constantly.

They are far apart.

Explanation;

-Neon is a chemical element with symbol Ne and atomic number 10, which means an atom of neon has 10 electrons and 10 proton. It is a noble gas.

-Neon is a colorless, odorless, inert monatomic gas under standard conditions.

- Neon is a light, very inert gas as it does not form compounds with other substances and is odorless. Neon glows when a high electrical voltage is passed through it.

You might be interested in

An automobile traveling 92.0 km/h has tires of 64.0 cm diameter. (a) What is the angular speed of the tires about their axles? (

Semenov [28]

Answer:

76.4035 m

Explanation:

r = Radius = 0.32 m

$\omega_f$ = Final angular velocity = 0

$\omega_i$ = Initial angular velocity = 92 km/h

$\alpha$ = Angular acceleration

$\theta$ = Angle of rotation

Angular speed is given by

$\omega=\dfrac{v}{r}\\\Rightarrow \omega=\dfrac{\dfrac{92}{3.6}}{0.32}\\\Rightarrow \omega=79.861\ rad/s$

The angular speed of the tires about their axles is 79.861 rad/s.

$\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{0^2-79.861^2}{2\times 2\pi \times 38}\\\Rightarrow \alpha=-13.355\ rad/s^2$

The magnitude of acceleration is 13.355 m/s²

Distance is given by

$d=\theta r\\\Rightarrow d=38\times 2\pi\times 0.32\\\Rightarrow d=76.4035\ m$

The distance moved while slowing down is 76.4035 m

6 0

3 years ago

What is air pressure?

Dmitry_Shevchenko [17]

Air Pressure is a force that is exerted onto your body by air molecules.

3 0

3 years ago

The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t

yuradex [85]

Answer: 104.026 m/s=374.49 km/h

Explanation:

When a body or object falls, basically two forces act on it:

1. The force of air friction, also called "drag force" $D$ :

$D={C}_{d}\frac{\rho V^{2} }{2}A$ (1)

Where:

$C_ {d}=0.7$ is the drag coefficient

$\rho=1.21 kg/m^{3}$ is the density of the fluid (air in this case)

$V$ is the velocity

$A=0.17 m^{2}$ is the transversal area of the object

So, this force is proportional to the transversal area of the falling element and to the square of the velocity.

2. Its weight due to the gravity force $W$ :

$W=m.g$ (2)

Where:

$m=79.5 kg$ is the mass of the object

$g=9.8 m/s^{2}$ is the acceleration due gravity

<h3>So, at the moment when the drag force equals the gravity force, the object will have its terminal velocity: </h3>

$D=W$ (3)

${C}_{d}\frac{\rho V^{2} }{2}A=m.g$ (4)

$V=\sqrt{\frac{2m.g}{\rho A{C}_{d}}}$ (5) This is the terminal velocity

Substituting the known values in (5):

$V=\sqrt{\frac{2(79.5 kg)(9.8 m/s^{2})}{(1.21 kg/m^{3})(0.17m^{2}){(0.7)}}$ (6)

Then:

$V=104.026 m/s$ This is the final velocity in meters per second

Now, let's find the final velocity in kilometers per hour, knowing $1 km=1000 m$ and $1 h=3600 s$ :

$V=104.026 \frac{m}{s} (\frac{1 km}{1000 m})(\frac{3600 s}{1 h})=374.49 km/h$ This is the final velocity in kilometers per hour.

4 0

3 years ago

An oil film on top of water has one patch that is much thinner than the wavelength of visible light. The index of refraction of

GenaCL600 [577]

Answer:

they indicate that the thickness is much less than the length of anything we have a destructive interference, bone has a dark area

Explanation:

Let's analyze the interaction of the ray reflected on the surface of the oil and at the bottom of the film, to know what kind of interference we have.

- When the beam passes from the air to the oil film, it has a phase change of 180 since the refractive index of the oil is greater than the refractive index of the air n = 1

- When the beam reaches the oil-water interface, the refractive impact of the water is oil cobs, therefore it has a 180 phase change

- in the oil film because the speed of the beam is different from that of air and the frequency in the air and oil is the same, since the propagation of a resonant type process, to meet the equation

v = λ f

The wavelength must change c = λ₀ f

c / v = λ₀ /λ

n = λ₀ /λ

λₙ = λ₀ / n

In general this type of reflection is almost normal to the surface, so we can calculate the optical path difference, if t is the thickness of the film, for constructive interference

2t = m λₙ + λₙ / 2 + λₙ / 2

The last two terms are for the phase change

2t / = (m + 1) λₙ

This is the condition to see a bright beam

For the first reflection m = 0

2t = λₙ

Therefore the minimum thickness of the film for constructive interference is λₙ / 2.

As they indicate that the thickness is much less than the length of anything we have a destructive interference, bone has a dark area

3 0

4 years ago

What records the difference between still air and air that is being rammed into the system?

Alex Ar [27]

Answer:

Still air is at atmospheric pressure and atmospheric temperature whereas rammed air has a higher pressure, higher density than the atmosphere and as a result, its temperature also increases.

Explanation:

Still air is at atmospheric pressure and atmospheric temperature whereas rammed air has a higher pressure than the atmosphere and as a result, its temperature also increases.

Rammed air is under pressure and has a higher density. Rammed air has a greater mass in less volume.

The rammed air is used in compressors and gas turbines to produce energy in the desired form.

3 0

4 years ago