I think it's mass...
The mass of an object refers to the amount of matter that is contained by the object; the weight of an object is the force of gravity acting upon that object. Mass is related to how much stuff is there and weight is related to the pull of the Earth (or any other planet) upon that stuff.
consider the west direction as positive direction of motion
V' = velocity of airplane relative to observer on ground = 580 mph
v = velocity of wind relative to observer on ground
V = average speed of airplane with no wind = 600 mph
relative velocity is given as
V' = V + v
inserting the values
580 = 600 + v
v = 580 - 600
v = - 20 mph
the negative sign indicates the direction of wind is opposite to direction of airplane , east
hence speed of wind is 20 mph in east direction.
Answer:
Effective half-time of the tracer is 3.6 days
Explanation:
The formula for calculating the decay due to excretion for the first process is ;
here ;
= initial number of tracers
Then to the second process ; we have :
The total decay is as a result of the overall process occurring ; we have :
------ (1)
here ;
Putting the values in (1);we have :
As we also know that:
![\frac{1}{t_{1/2}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bt_%7B1%2F2%7D%7D%20%3D%20%5Cfrac%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2B%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2A%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D)
![\frac{1}{t_{1/2}}_{effective}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bt_%7B1%2F2%7D%7D_%7Beffective%7D%7D%20%3D%20%5Cfrac%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2B%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D%7B%5Bt_%7B1%2F2%7D%5D_%7Bradiation%7D%2A%5Bt_%7B1%2F2%7D%5D_%7Bexcretion%7D%7D)
= 3.6 days
Answer:
0.08 N/C
Explanation:
Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,
E = Kq/r².............................. Equation 1
Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.
making q the subject of the equation,
q = Er²/k............................... Equation 2
Given: E = 2 N/C, r = 4 m,
Substitute into equation 2
q = 2(4)²/k
q = 32/k C.
When r is increased to 20 m,
E = k(32/k)/20²
E = 32/400
E = 0.08 N/C.
Hence the electric Field = 0.08 N/C
Ok you need a punnett square? its gonna be easy, create the square first, Then put the letters in their, When done message me
