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3 years ago

Name a metal that doesn't conduct electricity

1 answer:

8 0

Well all metals conduct electricity in some way whether it's big or small, but probley one that wouldn't connect the most would be aluminum.

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Physical properties can be observed

Alika [10]

Answer:

Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others. That is your answer! Thanks! :)

Explanation:

4 0

2 years ago

Read 2 more answers

A sample of gas X occupies 10 mº at a pressure of 120 kPa.

Mashutka [201]

Answer:

The new pressure of the gas comes out to be 400 KPa.

Explanation:

Initial volume of gas = V = $10\textrm{ m}^{3}$

Initial pressure of gas = P = 120 KPa

Final volume of gas = V' = $3\textrm{ m}^{3}$

Assuming temperature to be kept constant.

Assuming final pressure of the gas to be P' KPa

$PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}$

New pressure of gas = 400 KPa

5 0

2 years ago

True or false? Molecules are made of atoms of one type

Olegator [25]

Answer:

false

Explanation:

4 0

2 years ago

Read 2 more answers

The atoms, molecules, or compounds present at the start of a chemical reaction that participate in the reaction.

Art [367]

For the first one the answer is B. and the second one is D.

4 0

3 years ago

Read 2 more answers

The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?

Agata [3.3K]

Answer: The molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

Explanation:

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$PbI_2\rightleftharpoons Pb^{2+}+2I^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Pb^{2+}][I^-]^2$

We are given:

$K_{sp}=7.9\times 10^{-9}$

Putting values in above equation, we get:

$7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L$

Hence, the molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

3 0

2 years ago